从列表中的两个数据框，我需要减去两列并得到另一个数据框

Question

我有这些数据框：

df1 <- data.frame( value=c(1,2,3,4), income= c(12,14,51,12))
df2 <- data.frame( value=c(2,3,4,7), income= c(14,11,53,13))

我需要获取这个数据框：

df3
  value income
1   1   -12
2   2   0
3   3   -40
4   4   41
5   7   13

但是我使用了聚合函数，我得到了这个：

df3 <-do.call(rbind, l)%>% aggregate(income ~ value, ., FUN=diff)

  value income
1   1   numeric(0)
2   2   0
3   3   -40
4   4   41
5   7   numeric(0)

感谢您的帮助

Answer 1

基础 R 答案。

df3 <- merge(df2, df1, by = "value", all = TRUE)
df3[is.na(df3)] <- 0
df3[["income"]] <- df3[["income.x"]] - df3[["income.y"]]

tidyverse 答案。

library("tidyverse")

df3 <- full_join(df1, df2, by = "value") %>%
  replace_na(list(income.x = 0, income.y = 0)) %>%
  mutate(income = income.x - income.y)

data.table回答。

library("data.table")

DT1 <- data.table(value=c(1,2,3,4), income= c(12,14,51,12))
DT2 <- data.table(value=c(2,3,4,7), income= c(14,11,53,13))

DT3 <- merge(DT1, DT2, by = "value", all = TRUE)
DT3[is.na(DT3)] <- 0

DT3[, income := income.x - income.y]

从列表中的两个数据框，我需要减去两列并得到另一个数据框

From two dataframes inside a list, I need to substract two columns and get another dataframe

diff

aggregate

r