在 Android 6.0 中使用 Dagger2 初始化 Worker 时应用程序不断崩溃

App keeps crashing while initialising Worker with Dagger2 in Android 6.0

java.lang.ClassCastException: androidx.work.impl.workers.ConstraintTrackingWorker 无法转换为 androidx.work.Worker 在 java.lang.Class.asSubclass(Class.java:1486) 在 com.mpower.android.lpincrm.workers.DaggerWorkerFactory.createWorker(DaggerWorkerFactory.kt:38) 在 androidx.work.WorkerFactory.createWorkerWithDefaultFallback(WorkerFactory.java:83) 在 androidx.work.impl.WorkerWrapper.runWorker(WorkerWrapper.java:242) 在 androidx.work.impl.WorkerWrapper.run(WorkerWrapper.java:136) 在 androidx.work.impl.utils.SerialExecutor$Task.run(SerialExecutor.java:91) 在 java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113) 在 java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588) 在 java.lang.Thread.run(Thread.java:818)

createWorker() 的第一行出现错误:

override fun createWorker(appContext: Context, workerClassName: String, workerParameters: WorkerParameters): ListenableWorker? {
        val workerclass = Class.forName(workerClassName).asSubclass(Worker::class.java)
        val constructor = workerclass.getDeclaredConstructor(Context::class.java, WorkerParameters::class.java)
        val instance = constructor.newInstance(appContext, workerParameters)


    when (instance) {
        is MetaWorker -> {
            instance.treatmentMetaRepository = foo
            instance.newsRepository = foo1
            instance.geoDataRepository = foo2
            instance.medicineMetaRepository = foo3
            instance.preferenceUtil = preferenceUtil
        }
        is NotificationSchedulerWorker -> {
            instance.notificationRepository = notification
        }
        is SyncWorker -> {
            instance.syncAPIs = syncAPI
            instance.registrationAPI = registrationAPI
            instance.preferenceUtil = preferenceUtil
            instance.treatmentRepository = treatmentRepository
            instance.medicineRepository = medicineRepository
            instance.medicineDetailsRepository = medicineDetailsRepository
            instance.collectionRepository = collectionRepository
            instance.newVisitRepository = newVisitRepository
            instance.dueReceiptRepository = dueReceiptRepository
            instance.transportationRepository = transportationRepository  
        }
    }
    return instance
}

我的工人版本:

def work_version = "2.3.4"
implementation "androidx.work:work-runtime:$work_version"

您的 WorkerFactory 错误地假设应用程序创建的每个 ListenableWorker 子类也是 Worker 子类。事实证明,WorkManager 库包含此规则的一些例外情况,用作内部实现细节。

解决方法是将传递的工人 类 视为 ListenableWorker 的子 类,而不是 Worker

val workerclass = Class.forName(workerClassName).asSubclass(ListenableWorker::class.java)