在 Android 6.0 中使用 Dagger2 初始化 Worker 时应用程序不断崩溃
App keeps crashing while initialising Worker with Dagger2 in Android 6.0
java.lang.ClassCastException: androidx.work.impl.workers.ConstraintTrackingWorker 无法转换为 androidx.work.Worker
在 java.lang.Class.asSubclass(Class.java:1486)
在 com.mpower.android.lpincrm.workers.DaggerWorkerFactory.createWorker(DaggerWorkerFactory.kt:38)
在 androidx.work.WorkerFactory.createWorkerWithDefaultFallback(WorkerFactory.java:83)
在 androidx.work.impl.WorkerWrapper.runWorker(WorkerWrapper.java:242)
在 androidx.work.impl.WorkerWrapper.run(WorkerWrapper.java:136)
在 androidx.work.impl.utils.SerialExecutor$Task.run(SerialExecutor.java:91)
在 java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
在 java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
在 java.lang.Thread.run(Thread.java:818)
createWorker()
的第一行出现错误:
override fun createWorker(appContext: Context, workerClassName: String, workerParameters: WorkerParameters): ListenableWorker? {
val workerclass = Class.forName(workerClassName).asSubclass(Worker::class.java)
val constructor = workerclass.getDeclaredConstructor(Context::class.java, WorkerParameters::class.java)
val instance = constructor.newInstance(appContext, workerParameters)
when (instance) {
is MetaWorker -> {
instance.treatmentMetaRepository = foo
instance.newsRepository = foo1
instance.geoDataRepository = foo2
instance.medicineMetaRepository = foo3
instance.preferenceUtil = preferenceUtil
}
is NotificationSchedulerWorker -> {
instance.notificationRepository = notification
}
is SyncWorker -> {
instance.syncAPIs = syncAPI
instance.registrationAPI = registrationAPI
instance.preferenceUtil = preferenceUtil
instance.treatmentRepository = treatmentRepository
instance.medicineRepository = medicineRepository
instance.medicineDetailsRepository = medicineDetailsRepository
instance.collectionRepository = collectionRepository
instance.newVisitRepository = newVisitRepository
instance.dueReceiptRepository = dueReceiptRepository
instance.transportationRepository = transportationRepository
}
}
return instance
}
我的工人版本:
def work_version = "2.3.4"
implementation "androidx.work:work-runtime:$work_version"
您的 WorkerFactory
错误地假设应用程序创建的每个 ListenableWorker
子类也是 Worker
子类。事实证明,WorkManager
库包含此规则的一些例外情况,用作内部实现细节。
解决方法是将传递的工人 类 视为 ListenableWorker
的子 类,而不是 Worker
。
val workerclass = Class.forName(workerClassName).asSubclass(ListenableWorker::class.java)
java.lang.ClassCastException: androidx.work.impl.workers.ConstraintTrackingWorker 无法转换为 androidx.work.Worker 在 java.lang.Class.asSubclass(Class.java:1486) 在 com.mpower.android.lpincrm.workers.DaggerWorkerFactory.createWorker(DaggerWorkerFactory.kt:38) 在 androidx.work.WorkerFactory.createWorkerWithDefaultFallback(WorkerFactory.java:83) 在 androidx.work.impl.WorkerWrapper.runWorker(WorkerWrapper.java:242) 在 androidx.work.impl.WorkerWrapper.run(WorkerWrapper.java:136) 在 androidx.work.impl.utils.SerialExecutor$Task.run(SerialExecutor.java:91) 在 java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113) 在 java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588) 在 java.lang.Thread.run(Thread.java:818)
createWorker()
的第一行出现错误:
override fun createWorker(appContext: Context, workerClassName: String, workerParameters: WorkerParameters): ListenableWorker? {
val workerclass = Class.forName(workerClassName).asSubclass(Worker::class.java)
val constructor = workerclass.getDeclaredConstructor(Context::class.java, WorkerParameters::class.java)
val instance = constructor.newInstance(appContext, workerParameters)
when (instance) {
is MetaWorker -> {
instance.treatmentMetaRepository = foo
instance.newsRepository = foo1
instance.geoDataRepository = foo2
instance.medicineMetaRepository = foo3
instance.preferenceUtil = preferenceUtil
}
is NotificationSchedulerWorker -> {
instance.notificationRepository = notification
}
is SyncWorker -> {
instance.syncAPIs = syncAPI
instance.registrationAPI = registrationAPI
instance.preferenceUtil = preferenceUtil
instance.treatmentRepository = treatmentRepository
instance.medicineRepository = medicineRepository
instance.medicineDetailsRepository = medicineDetailsRepository
instance.collectionRepository = collectionRepository
instance.newVisitRepository = newVisitRepository
instance.dueReceiptRepository = dueReceiptRepository
instance.transportationRepository = transportationRepository
}
}
return instance
}
我的工人版本:
def work_version = "2.3.4"
implementation "androidx.work:work-runtime:$work_version"
您的 WorkerFactory
错误地假设应用程序创建的每个 ListenableWorker
子类也是 Worker
子类。事实证明,WorkManager
库包含此规则的一些例外情况,用作内部实现细节。
解决方法是将传递的工人 类 视为 ListenableWorker
的子 类,而不是 Worker
。
val workerclass = Class.forName(workerClassName).asSubclass(ListenableWorker::class.java)