SQL count() 多个 where 值
SQL count() multiple where values
我想计算 VOTE1
和 VOTE2
并显示在我的人口统计中。如果它只在 VOTE1
的地方工作,但如果我在 DataGrid 上添加 VOTE2
值不显示:
jokenfindthis("SELECT
` PRK` as 'Purok'
,COUNT(*) as 'No. of households'
FROM `tblresidence`
where VOTE1 & VOTE2 ='" & ComboBox1.SelectedValue & "'
GROUP BY `Purok` ")
下面是未添加VOTE2
时的示例代码:
代码中只有 VOTE1
时代码有效:
这是我的组合框:
我的VOTE1
和VOTE2
ComboBox我要算了。选择是或否。我想显示是或否的数字:
正如 pagalprogrammer 提到的,您可能希望将 WHERE
语句分成两部分:
jokenfindthis("SELECT
` PRK` as 'Purok'
,COUNT(*) as 'No. of households'
FROM `tblresidence`
where VOTE1 ='" & ComboBox1.SelectedValue & "'
AND VOTE2 ='" & ComboBox1.SelectedValue & "'
GROUP BY `Purok` ")
通过选择 VOTE1 = AND VOTE2 =,您只会看到 VOTE1 也等于 VOTE2 的结果。你真的想这样做吗?
在哪里
投票 1 ='" & ComboBox1.SelectedValue & "'
或 VOTE2 ='" & ComboBox1.SelectedValue & "'
诚然,我想我只是部分理解了这个问题,所以请提前原谅。如果您尝试分别报告 Vote1 和 Vote2 的结果,则需要在 select 语句中将它们分开。
jokenfindthis("SELECT
` PRK` as 'Purok'
, sum(case when VOTE1 ='" & ComboBox1.SelectedValue & "' then 1 else 0 end) as 'No. of households - Vote 1'
, sum(case when VOTE2 ='" & ComboBox2.SelectedValue & "' then 1 else 0 end) as 'No. of households - Vote 2'
FROM `tblresidence`
where VOTE1 ='" & ComboBox1.SelectedValue & "'
or VOTE2 ='" & ComboBox2.SelectedValue & "'
GROUP BY `Purok` ")
如果您要计算 Vote1 或 Vote2 满足您条件的住宅,那么我会尝试以下方法
jokenfindthis("SELECT
` PRK` as 'Purok'
, count(*) as 'No. of households'
FROM `tblresidence`
where VOTE1 ='" & ComboBox1.SelectedValue & "'
or VOTE2 ='" & ComboBox1.SelectedValue & "'
GROUP BY `Purok` ")
我想计算 VOTE1
和 VOTE2
并显示在我的人口统计中。如果它只在 VOTE1
的地方工作,但如果我在 DataGrid 上添加 VOTE2
值不显示:
jokenfindthis("SELECT
` PRK` as 'Purok'
,COUNT(*) as 'No. of households'
FROM `tblresidence`
where VOTE1 & VOTE2 ='" & ComboBox1.SelectedValue & "'
GROUP BY `Purok` ")
下面是未添加VOTE2
时的示例代码:
代码中只有 VOTE1
时代码有效:
这是我的组合框:
我的VOTE1
和VOTE2
ComboBox我要算了。选择是或否。我想显示是或否的数字:
正如 pagalprogrammer 提到的,您可能希望将 WHERE
语句分成两部分:
jokenfindthis("SELECT
` PRK` as 'Purok'
,COUNT(*) as 'No. of households'
FROM `tblresidence`
where VOTE1 ='" & ComboBox1.SelectedValue & "'
AND VOTE2 ='" & ComboBox1.SelectedValue & "'
GROUP BY `Purok` ")
通过选择 VOTE1 = AND VOTE2 =,您只会看到 VOTE1 也等于 VOTE2 的结果。你真的想这样做吗?
在哪里
投票 1 ='" & ComboBox1.SelectedValue & "'
或 VOTE2 ='" & ComboBox1.SelectedValue & "'
诚然,我想我只是部分理解了这个问题,所以请提前原谅。如果您尝试分别报告 Vote1 和 Vote2 的结果,则需要在 select 语句中将它们分开。
jokenfindthis("SELECT
` PRK` as 'Purok'
, sum(case when VOTE1 ='" & ComboBox1.SelectedValue & "' then 1 else 0 end) as 'No. of households - Vote 1'
, sum(case when VOTE2 ='" & ComboBox2.SelectedValue & "' then 1 else 0 end) as 'No. of households - Vote 2'
FROM `tblresidence`
where VOTE1 ='" & ComboBox1.SelectedValue & "'
or VOTE2 ='" & ComboBox2.SelectedValue & "'
GROUP BY `Purok` ")
如果您要计算 Vote1 或 Vote2 满足您条件的住宅,那么我会尝试以下方法
jokenfindthis("SELECT
` PRK` as 'Purok'
, count(*) as 'No. of households'
FROM `tblresidence`
where VOTE1 ='" & ComboBox1.SelectedValue & "'
or VOTE2 ='" & ComboBox1.SelectedValue & "'
GROUP BY `Purok` ")