MSSQL 服务器SQL 查询如何使用"group by"
MSSQL server SQL query how to utilize "group by"
Table Data
My_table_data.
testdate plant value
2020-05-14 02:00:00.000 1 68
2020-05-14 01:00:00.000 3 115
2020-05-14 02:00:00.000 2 107
2020-05-14 03:00:00.000 2 102
2020-05-14 05:00:00.000 2 104
2020-05-14 06:00:00.000 2 111
2020-05-14 08:00:00.000 1 74
2020-05-14 08:00:00.000 2 114
2020-05-14 09:00:00.000 1 70
2020-05-14 09:00:00.000 2 114
2020-05-14 03:00:00.000 3 106
2020-05-14 03:00:00.000 3 102
2020-05-15 02:00:00.000 2 108
2020-05-14 05:00:00.000 1 74
2020-05-14 04:00:00.000 3 96
2020-05-14 04:00:00.000 3 97
2020-05-14 06:00:00.000 1 80
2020-05-14 03:00:00.000 1 77
2020-05-14 06:00:00.000 3 102
我是复杂 SQL 查询短语的新手。如何实现如下结果。
条件
1.时间戳最新数据(小时)
2. 每株单行。
WITH data AS(
SELECT testdate, plant, value, (DATEPART(HOUR,testdate))AS dH FROM My_table_data
WHERE testdate >= (SELECT CONVERT(DATETIME, CONVERT(DATE, GETDATE()), 120))
)
SELECT data.testdate, data.plant, data.value from data
WHERE data.dH= (SELECT MAX(data.dH) FROM data)
GROUP BY data.plant
ORDER BY data.plant DESC;
报错!!
testdate Plant value
2020-05-14 09:00:00.000 1 70
2020-05-14 09:00:00.000 2 114
2020-05-14 06:00:00.000 3 102
我觉得这应该很简单
with maxData
AS
(
SELECT MAX(testDate) as testDate, plantId
FROM My_table_data
GROUP BY plantId
)
select
t.testDate,
t.plantId,
t.value
from My_table_data t
INNER JOIN maxData m
on t.testDate = m.testDate
and t.plantId = m.plantId
order by plantId
这样做是使用 CTE 查找每个 plantId
的最大日期,然后将该信息加入原始 table 以查找与该 plantId 对应的 value
和日期。
Table Data
My_table_data.
testdate plant value
2020-05-14 02:00:00.000 1 68
2020-05-14 01:00:00.000 3 115
2020-05-14 02:00:00.000 2 107
2020-05-14 03:00:00.000 2 102
2020-05-14 05:00:00.000 2 104
2020-05-14 06:00:00.000 2 111
2020-05-14 08:00:00.000 1 74
2020-05-14 08:00:00.000 2 114
2020-05-14 09:00:00.000 1 70
2020-05-14 09:00:00.000 2 114
2020-05-14 03:00:00.000 3 106
2020-05-14 03:00:00.000 3 102
2020-05-15 02:00:00.000 2 108
2020-05-14 05:00:00.000 1 74
2020-05-14 04:00:00.000 3 96
2020-05-14 04:00:00.000 3 97
2020-05-14 06:00:00.000 1 80
2020-05-14 03:00:00.000 1 77
2020-05-14 06:00:00.000 3 102
我是复杂 SQL 查询短语的新手。如何实现如下结果。 条件 1.时间戳最新数据(小时) 2. 每株单行。
WITH data AS(
SELECT testdate, plant, value, (DATEPART(HOUR,testdate))AS dH FROM My_table_data
WHERE testdate >= (SELECT CONVERT(DATETIME, CONVERT(DATE, GETDATE()), 120))
)
SELECT data.testdate, data.plant, data.value from data
WHERE data.dH= (SELECT MAX(data.dH) FROM data)
GROUP BY data.plant
ORDER BY data.plant DESC;
报错!!
testdate Plant value
2020-05-14 09:00:00.000 1 70
2020-05-14 09:00:00.000 2 114
2020-05-14 06:00:00.000 3 102
我觉得这应该很简单
with maxData
AS
(
SELECT MAX(testDate) as testDate, plantId
FROM My_table_data
GROUP BY plantId
)
select
t.testDate,
t.plantId,
t.value
from My_table_data t
INNER JOIN maxData m
on t.testDate = m.testDate
and t.plantId = m.plantId
order by plantId
这样做是使用 CTE 查找每个 plantId
的最大日期,然后将该信息加入原始 table 以查找与该 plantId 对应的 value
和日期。