连接列并添加数字 awk

Question

我有一个 csv 文件：

number1;number2;min_length;max_length
"40";"1801";8;8  
"40";"182";8;8  
"42";"32";6;8  
"42";"4";6;6  
"43";"691";9;9

我希望输出为：

4018010000;4018019999  
4018200000;4018299999  
42320000;42329999
423200000;423299999
4232000000;4232999999
42400000;42499999  
43691000000;43691999999

因此新文件将包含：

column_1 = a concatenation of old_column_1 + old_column_2 + a number of "0" equal to (old_column_3 - length of the old_column_2)

column_2 = a concatenation of old_column_1 + old_column_2 + a number of "9" equal to (old_column_3 - length of the old_column_2) , when min_length = max_length. And when min_length is not equal with max_length , I need to take into account all the possible lengths. So for the line "42";"32";6;8 , all the lengths are: 6,7 and 8.

此外，我需要删除所有引号。

我试过像那样粘贴和剪切：

paste -d ";" <(cut -f1,2 -d ";" < file1) > file2

用于连接前两列，但我认为使用 awk 更容易。但是，我不知道该怎么做。任何帮助都值得赞赏。谢谢！

编辑：实际上，在输入中添加了第 4 列。

Answer 1

您可以使用这个 awk:

awk 'function padstr(ch, len, s) {
   s = sprintf("%*s", len, "")
   gsub(/ /, ch, s)
   return s
}
BEGIN {
   FS=OFS=";"
}
{
   gsub(/"/, "");
   for (i=0; i<=(-); i++) {
      d =  - length() + i
      print   padstr("0", d),   padstr("9", d)
   }
}' file

4018010000;4018019999
4018200000;4018299999
42320000;42329999
423200000;423299999
4232000000;4232999999
42400000;42499999
43691000000;43691999999

Answer 2

使用 awk:

awk '
    BEGIN{FS = OFS = ";"}  # set field separator and output field separator to be ";"
    {
        [=10=] = gensub("\"", "", "g"); # Drop double quotes
        s = ; # The range header number
        l = -length(); # Number of zeros or 9s to be appended
        l = 10^l; # Get 10 raised to that number
        print s*l, (s+1)*l-1; # Adding n zeros is multiplication by 10^n
                              # Adding n nines is multipliaction by 10^n + (10^n - 1)
    }' input.txt

内嵌注释的说明。

连接列并添加数字 awk

Concatenate columns and adds digits awk

awk

add

concat

cut