PHP 从字符串中查找月份和年份？

Question

这是我迄今为止尝试从任何类型的字符串中获取年份的方法。

<?php

  $variable = [
      'Well year is 1967 month jan',
      'year is 1876 but month January',
      'HOLLA April Evening 2017',
      'DOLLA-May 2020',
      'OH-YESApril 2019 (IGNORE)',
      'Just a sample String without year ok lets just add 1'
  ];
  foreach ($variable as $value) {
      if(ContainsNumbers($value)){
           $input = preg_replace('/^[^\d]*(\d{4}).*$/', '', $value);
            $input = (int)$input;
                if($input>1000 && $input<2100)
                {
                   var_dump($input);
                }                   
      } 
  }
  function ContainsNumbers($String){
    return preg_match('/\d/', $String) > 0;
}
?>

这是上面代码

的输出

int(1967)
int(1876)
int(2017)
int(2020)
int(2019)

我现在唯一想要的就是从字符串中获取月份。一个月来，我从这个 link 获得了帮助，但到目前为止运气不好 :- 我不知道要在 $data

中添加什么

$str = 'December 2012 Name: Jack Brown';
$ptr = "/^(?P<month>:Jan(?:uary)?|Feb(?:ruary)?|Dec(?:ember)?) (?P<year>:19[7-9]\d|2\d{3}) (Name:(?P<name>(.*)))/";
 var_dumb(preg_match($ptr, $str, $data););

Here is a play ground

Answer 1

传统上，几乎每个人都将第三个参数称为preg_match $matches，所以我将在这里使用命名法。

如果 RegEx 匹配，第三个参数将是一个数组，其中包含每个项目的数字索引，以及命名索引（如果您有任何命名匹配项）。所以您正在寻找：

if(preg_match($ptr, $str, $matches)){
    var_dump($matches);
}

哪个会给你：

Array
(
    [0] => December 2012 Name: Jack Brown
    [month] => December
    [1] => December
    [year] => 2012
    [2] => 2012
    [3] => Name: Jack Brown
    [name] =>  Jack Brown
    [4] =>  Jack Brown
    [5] =>  Jack Brown
)

Answer 2

好吧，Chris haas 已经解释得很清楚了，但是任何人都想使用数组方法，那么请使用这个：-

<?php
$variable = [
      'Well year is 1967 month jan',
      'year is 1876 but month January',
      'HOLLA April Evening 2017',
      'DOLLA-May 2020',
      'OH-YESApril 2019 (IGNORE)',
      'Just a sample String without year ok lets just add 1'
  ];
  $months = array(
    'January' => 'jan',
    'February' => 'feb',
    'March' => 'mar',
    'April' => 'apr',
    'May' => 'may',
    'June' => 'jun',
    'July ' => 'jul',
    'August' => 'aug',
    'September' => 'sep',
    'October' => 'oct',
    'November' => 'nov',
    'December' => 'dec',
);
  foreach ($variable as $string) {
      foreach($months as $key => $value){
            if (strpos($string, $value) !== false) {
               var_dump($value) ;
            }
              if (strpos($string, $key) !== false) {
                 var_dump($value) ;
            }
  }

}
die();

?>

输出

string(3) "jan"
string(3) "jan"
string(3) "apr"
string(3) "may"
string(3) "apr"

PHP 从字符串中查找月份和年份？

PHP finding month and year from a string?

php

regex

preg-match