我如何使用 Alamofire Router 来组织 API 调用? [swift/Alamofire 5]
How can I use Alamofire Router to organize the API call? [swift/ Alamofire5]
我正在尝试将我的 AF 请求 转换为 Router 结构以获得更清洁的项目。我收到以下错误:
Value of protocol type 'Any' cannot conform to 'Encodable'; only struct/enum/class types can conform to protocols.
请帮助我修复代码。谢谢!
我的 URL 将有一个 用户名 的占位符, 密码 将在 body
中发送。响应将是 Bool (success), username and bearer token
。
下面是我的AF请求:
let username = usernameTextField.text
let password = passwordTextField.text
let loginParams = ["password":"\(password)"]
AF.request("https://example.com/users/\(username)/login",
method: .post,
parameters: loginParams,
encoder: JSONParameterEncoder.default,
headers: nil, interceptor: nil).response { response in
switch response.result {
case .success:
if let data = response.data {
do {
let userLogin = try JSONDecoder().decode(UsersLogin.self, from: data)
if userLogin.success == true {
defaults.set(username, forKey: "username")
defaults.set(password, forKey: "password")
defaults.set(userLogin.token, forKey: "token")
print("Successfully get token.")
} else {
//show alert
print("Failed to get token with incorrect login info.")
}
} catch {
print("Error: \(error)")
}
}
case .failure(let error):
//show alert
print("Failed to get token.")
print(error.errorDescription as Any)
}
}
到目前为止,我有什么可以转换为 AF 路由器 结构:
import Foundation
import Alamofire
enum Router: URLRequestConvertible {
case login(username: String, password: String)
var method: HTTPMethod {
switch self {
case .login:
return .post
}
}
var path: String {
switch self {
case .login(let username):
return "/users/\(username)/login"
}
}
var parameters: Parameters? {
switch self {
case .login(let password):
return ["password": password]
}
}
// MARK: - URLRequestConvertible
func asURLRequest() throws -> URLRequest {
let url = try Constants.ProductionServer.baseURL.asURL()
var request = URLRequest(url: url.appendingPathComponent(path))
// HTTP Method
request.httpMethod = method.rawValue
// Common Headers
request.setValue(ContentType.json.rawValue, forHTTPHeaderField: HTTPHeaderField.acceptType.rawValue)
request.setValue(ContentType.json.rawValue, forHTTPHeaderField: HTTPHeaderField.contentType.rawValue)
// Parameters
switch self {
case .login(let password):
request = try JSONParameterEncoder().encode(parameters, into: request) //where I got the error
}
return request
}
}
class APIClient {
static func login(password: String, username: String, completion: @escaping (Result<UsersLogin, AFError>) -> Void) {
AF.request(Router.login(username: username, password: password)).responseDecodable { (response: DataResponse<UsersLogin, AFError>) in
completion(response.result)
}
}
}
LoginViewController
Class(我替换了 AF.request 代码)
APIClient.login(password: password, username: username) { result in
switch result {
case .success(let user):
print(user)
case .failure(let error):
print(error.localizedDescription)
}
可编码UsersLogin
型号
struct UsersLogin: Codable {
let success: Bool
let username: String
let token: String?
enum CodingKeys: String, CodingKey {
case success = "success"
case username = "username"
case token = "token"
}
}
您不能将 Parameters
词典与 Encodable
类型一起使用,因为 [String: Encodable]
的词典不是 Encodable
,如错误所述。我建议将 asURLRequest
过程的那一步移到一个单独的函数中,例如:
func encodeParameters(into request: inout URLRequest) {
switch self {
case let .login(parameters):
request = try JSONParameterEncoder().encode(parameters, into: request)
}
}
不幸的是,对于具有许多路由的路由器来说,这并不能很好地扩展,所以我通常将我的路由分解成小的枚举,并将我的参数移动到单独的类型中,这些类型与路由器结合产生 URLRequest
.
花了我一段时间但终于修好了。我也清理了代码。
enum Router: URLRequestConvertible {
case login([String: String], String)
var baseURL: URL {
return URL(string: "https://example.com")!
}
var method: HTTPMethod {
switch self {
case .login:
return .post
}
}
var path: String {
switch self {
case .login(_, let username):
return "/users/\(username)/login"
}
}
func asURLRequest() throws -> URLRequest {
print(path)
let urlString = baseURL.appendingPathComponent(path).absoluteString.removingPercentEncoding!
let url = URL(string: urlString)
var request = URLRequest(url: url!)
request.method = method
switch self {
case let .login(parameters, _):
request = try JSONParameterEncoder().encode(parameters, into: request)
}
return request
}
}
用法
let username = usernameTextField.text
AF.request(Router.login(["password": password], username)).responseDecodable(of: UsersLogin.self) { (response) in
if let userLogin = response.value {
switch userLogin.success {
case true:
print("Successfully get token.")
case false:
print("Failed to get token with incorrect login info.")
}
} else {
print("Failed to get token.")
}
}
我用这种方法解决了类似的问题。我创建了一个协议 Routable
enum EncodeMode {
case encoding(parameterEncoding: ParameterEncoding, parameters: Parameters?)
case encoder(parameterEncoder: ParameterEncoder, parameter: Encodable)
}
protocol Routeable: URLRequestConvertible {
var baseURL: URL { get }
var path: String { get }
var method: HTTPMethod { get }
var encodeMode: EncodeMode { get }
}
extension Routeable {
// MARK: - URLRequestConvertible
func asURLRequest() throws -> URLRequest {
let url = baseURL.appendingPathComponent(path)
var urlRequest: URLRequest
switch encodeMode {
case .encoding(let parameterEncoding, let parameters):
urlRequest = try parameterEncoding.encode(URLRequest(url: url), with: parameters)
case .encoder(let parameterEncoder, let parameter):
urlRequest = URLRequest(url: url)
urlRequest = try parameterEncoder.encode(AnyEncodable(parameter), into: urlRequest)
}
urlRequest.method = method
return urlRequest
}
}
我的路由器看起来像这个
enum WifiInterfacesRouter: Routeable {
case listActive(installationId: Int16?)
case insert(interface: WifiInterface)
var encodeMode: EncodeMode {
switch self {
case .listActive(let installationId):
guard let installationId = installationId else {
return .encoding(parameterEncoding: URLEncoding.default, parameters: nil)
}
return .encoding(parameterEncoding: URLEncoding.default, parameters: ["idInstallation": installationId])
case .insert(let interface):
return .encoder(parameterEncoder: JSONParameterEncoder.default, parameter: interface)
}
}
var baseURL: URL {
return URL(string: "www.example.com/wifiInterfaces")!
}
var method: HTTPMethod {
switch self {
case .listActive: return .get
case .insert: return .post
}
}
var path: String {
switch self {
case .listActive: return "listActive"
case .insert: return "manage"
}
}
}
解决构建错误
Protocol 'Encodable' as a type cannot conform to the protocol itself
我使用了有用的 AnyCodable 库。 Codable
.
的类型擦除实现
我正在尝试将我的 AF 请求 转换为 Router 结构以获得更清洁的项目。我收到以下错误:
Value of protocol type 'Any' cannot conform to 'Encodable'; only struct/enum/class types can conform to protocols.
请帮助我修复代码。谢谢!
我的 URL 将有一个 用户名 的占位符, 密码 将在 body
中发送。响应将是 Bool (success), username and bearer token
。
下面是我的AF请求:
let username = usernameTextField.text
let password = passwordTextField.text
let loginParams = ["password":"\(password)"]
AF.request("https://example.com/users/\(username)/login",
method: .post,
parameters: loginParams,
encoder: JSONParameterEncoder.default,
headers: nil, interceptor: nil).response { response in
switch response.result {
case .success:
if let data = response.data {
do {
let userLogin = try JSONDecoder().decode(UsersLogin.self, from: data)
if userLogin.success == true {
defaults.set(username, forKey: "username")
defaults.set(password, forKey: "password")
defaults.set(userLogin.token, forKey: "token")
print("Successfully get token.")
} else {
//show alert
print("Failed to get token with incorrect login info.")
}
} catch {
print("Error: \(error)")
}
}
case .failure(let error):
//show alert
print("Failed to get token.")
print(error.errorDescription as Any)
}
}
到目前为止,我有什么可以转换为 AF 路由器 结构:
import Foundation
import Alamofire
enum Router: URLRequestConvertible {
case login(username: String, password: String)
var method: HTTPMethod {
switch self {
case .login:
return .post
}
}
var path: String {
switch self {
case .login(let username):
return "/users/\(username)/login"
}
}
var parameters: Parameters? {
switch self {
case .login(let password):
return ["password": password]
}
}
// MARK: - URLRequestConvertible
func asURLRequest() throws -> URLRequest {
let url = try Constants.ProductionServer.baseURL.asURL()
var request = URLRequest(url: url.appendingPathComponent(path))
// HTTP Method
request.httpMethod = method.rawValue
// Common Headers
request.setValue(ContentType.json.rawValue, forHTTPHeaderField: HTTPHeaderField.acceptType.rawValue)
request.setValue(ContentType.json.rawValue, forHTTPHeaderField: HTTPHeaderField.contentType.rawValue)
// Parameters
switch self {
case .login(let password):
request = try JSONParameterEncoder().encode(parameters, into: request) //where I got the error
}
return request
}
}
class APIClient {
static func login(password: String, username: String, completion: @escaping (Result<UsersLogin, AFError>) -> Void) {
AF.request(Router.login(username: username, password: password)).responseDecodable { (response: DataResponse<UsersLogin, AFError>) in
completion(response.result)
}
}
}
LoginViewController
Class(我替换了 AF.request 代码)
APIClient.login(password: password, username: username) { result in
switch result {
case .success(let user):
print(user)
case .failure(let error):
print(error.localizedDescription)
}
可编码UsersLogin
型号
struct UsersLogin: Codable {
let success: Bool
let username: String
let token: String?
enum CodingKeys: String, CodingKey {
case success = "success"
case username = "username"
case token = "token"
}
}
您不能将 Parameters
词典与 Encodable
类型一起使用,因为 [String: Encodable]
的词典不是 Encodable
,如错误所述。我建议将 asURLRequest
过程的那一步移到一个单独的函数中,例如:
func encodeParameters(into request: inout URLRequest) {
switch self {
case let .login(parameters):
request = try JSONParameterEncoder().encode(parameters, into: request)
}
}
不幸的是,对于具有许多路由的路由器来说,这并不能很好地扩展,所以我通常将我的路由分解成小的枚举,并将我的参数移动到单独的类型中,这些类型与路由器结合产生 URLRequest
.
花了我一段时间但终于修好了。我也清理了代码。
enum Router: URLRequestConvertible {
case login([String: String], String)
var baseURL: URL {
return URL(string: "https://example.com")!
}
var method: HTTPMethod {
switch self {
case .login:
return .post
}
}
var path: String {
switch self {
case .login(_, let username):
return "/users/\(username)/login"
}
}
func asURLRequest() throws -> URLRequest {
print(path)
let urlString = baseURL.appendingPathComponent(path).absoluteString.removingPercentEncoding!
let url = URL(string: urlString)
var request = URLRequest(url: url!)
request.method = method
switch self {
case let .login(parameters, _):
request = try JSONParameterEncoder().encode(parameters, into: request)
}
return request
}
}
用法
let username = usernameTextField.text
AF.request(Router.login(["password": password], username)).responseDecodable(of: UsersLogin.self) { (response) in
if let userLogin = response.value {
switch userLogin.success {
case true:
print("Successfully get token.")
case false:
print("Failed to get token with incorrect login info.")
}
} else {
print("Failed to get token.")
}
}
我用这种方法解决了类似的问题。我创建了一个协议 Routable
enum EncodeMode {
case encoding(parameterEncoding: ParameterEncoding, parameters: Parameters?)
case encoder(parameterEncoder: ParameterEncoder, parameter: Encodable)
}
protocol Routeable: URLRequestConvertible {
var baseURL: URL { get }
var path: String { get }
var method: HTTPMethod { get }
var encodeMode: EncodeMode { get }
}
extension Routeable {
// MARK: - URLRequestConvertible
func asURLRequest() throws -> URLRequest {
let url = baseURL.appendingPathComponent(path)
var urlRequest: URLRequest
switch encodeMode {
case .encoding(let parameterEncoding, let parameters):
urlRequest = try parameterEncoding.encode(URLRequest(url: url), with: parameters)
case .encoder(let parameterEncoder, let parameter):
urlRequest = URLRequest(url: url)
urlRequest = try parameterEncoder.encode(AnyEncodable(parameter), into: urlRequest)
}
urlRequest.method = method
return urlRequest
}
}
我的路由器看起来像这个
enum WifiInterfacesRouter: Routeable {
case listActive(installationId: Int16?)
case insert(interface: WifiInterface)
var encodeMode: EncodeMode {
switch self {
case .listActive(let installationId):
guard let installationId = installationId else {
return .encoding(parameterEncoding: URLEncoding.default, parameters: nil)
}
return .encoding(parameterEncoding: URLEncoding.default, parameters: ["idInstallation": installationId])
case .insert(let interface):
return .encoder(parameterEncoder: JSONParameterEncoder.default, parameter: interface)
}
}
var baseURL: URL {
return URL(string: "www.example.com/wifiInterfaces")!
}
var method: HTTPMethod {
switch self {
case .listActive: return .get
case .insert: return .post
}
}
var path: String {
switch self {
case .listActive: return "listActive"
case .insert: return "manage"
}
}
}
解决构建错误
Protocol 'Encodable' as a type cannot conform to the protocol itself
我使用了有用的 AnyCodable 库。 Codable
.