在 R 的循环中重新编码变量

Question

我想一起重新编码几个变量。所有这些变量都将经历相同的重新编码变化。为此，我遵循了下面的主题。下面的线程描述了两种方法。 1).使用列号 2).使用变量名

我都试过了，但我收到一条错误消息。

1) 和 2) 的错误消息。 (function (var, recodes, as.factor, as.numeric = TRUE, levels) 错误：未使用的参数 (2 = "1", 3 = "1", 1 = "0", 4 = "0", na.rm = TRUE )

#Uploading libraries
library(dplyr)
library(magrittr)
library(plyr)
library(readxl)
library(tidyverse)

#Importing file
mydata <- read_excel("CCorr_Data.xlsx")
df <- data.frame(mydata)
attach(df)

#replacing codes for variables
df %>%
  mutate_at(c(1:7), recode, '2'='1', '3'='1', '1'='0', '4'='0', na.rm = TRUE) %>%
  mutate_at(c(15:24), recode, '2'='0', na.rm = TRUE)


df %>% 
  mutate_at(vars(E301, E302, E303), recode,'2'='1', '3'='1', '1'='0', '4'='0', na.rm = TRUE) %>%
  mutate_at(vars(B201, B202, B203), recode, '2'='0', na.rm = TRUE)

谁能告诉我哪里错了？

在我的数据集中有缺失值，这就是我包含 na.rm = T 的原因。我什至尝试不包含缺失值命令，即使那样错误信息也是一样的。

请参阅下面的示例数据。

structure(list(Country = c(1, 1, 1, 1, 1, 1), HHID = c("12ae5148e245079f-122042", 
"12ae5148e245079f-123032", "12ae5148e245079f-123027", "12ae5148e245079f-123028", 
"12ae5148e245079f-N123001", "12ae5148e245079f-123041"), HHCode = c("122042", 
"123032", "123027", "123028", "N123001", "123041"), A103 = c(2, 
2, 2, 2, 2, 2), A104 = c("22", "23", "23", "23", "23", "23"), 
    Community = c("Mehmada", "Dhobgama", "Dhobgama", "Dhobgama", 
    "Dhobgama", "Dhobgama"), E301 = c(3, 3, 3, 3, 3, 3), E302 = c(3, 
    2, 4, 4, 3, 3), E303 = c(3, 2, 3, 3, 3, 3), E304 = c(3, 4, 
    4, 4, 3, 3), E305 = c(3, 2, 3, 3, 3, 3), E306 = c(3, 3, 3, 
    3, 3, 3), E307 = c(3, 3, 3, 3, 3, 3), E308 = c(3, 1, 3, 3, 
    3, 3), B201.1 = c(NA, 1, 1, 1, 1, 1), B202.1 = c(NA, 1, 1, 
    1, 1, 1), B203.1 = c(NA, 1, 1, 2, 2, 1), B204.1 = c(NA, 2, 
    1, 2, 1, 1), B205.1 = c(NA, 2, 1, 2, 2, 2), B206.1 = c(NA, 
    1, 1, 1, 2, 1), B207.1 = c(NA, 2, 1, 2, 2, 1), B208.1 = c(NA, 
    2, 2, 2, 2, 2), B209.1 = c(NA, 2, 1, 1, 1, 1), B210.1 = c(NA, 
    1, 1, 1, 1, 1)), row.names = c(NA, 6L), class = "data.frame")
    ```

Answer 1

尝试使用：

library(dplyr)

df %>%
  mutate_at(1:7, recode, '2'='1', '3'='1', '1'='0', '4'='0') %>%
  mutate_at(15:24, recode, '2'='0')

Answer 2

问题出在 na.rm = TRUE，recode 没有那个参数

library(dplyr)   
df %>% 
  mutate_at(vars(E301, E302, E303), recode,'2'='1', '3'='1', '1'='0', '4'='0') %>%
  mutate_at(vars(B201, B202, B203), recode, '2'='0')

在 R 的循环中重新编码变量

recoding variables in a loop in R

loops

r

dplyr

recode