我们可以多次使用 re.sub 而不是使用 str.replace

Question

import re
a = ["%!It depends%% on what you m\ean by dying.",
     "It is widely~ read and at the top_x000D_ of all the search%%__ engines.",
     "\H~owever, Wikipedia has internal problems",
     "%%a+b!=a-b"]
p = [((((((str(a[i]).replace("%!", "")).replace("%", ""))
     .replace("~", "")).replace("_x000D_","")).replace("__", ""))
     .replace("\", "")) for i in range(len(a)) if a[i] != ""]
print(p)

Answer 1

是的，您可以改用 re.sub

p2 = [re.sub(r"%!|%|~|_x000D_|__|\", "", str(a[i])) for i in range(len(a)) if a[i] != ""]

有关详细信息，请阅读此处的文档：https://docs.python.org/3/library/re.html#re.sub

Answer 2

既然你导入了 re 包，我想你想用正则表达式的方式来做。

to_replace = ['%!', '%', '~', '_x000D_', '__', '\']
to_replace = ")|(".join(map(re.escape, to_replace))
p = [re.sub(f'({to_replace})', '', a[i]) for i in range(len(a)) if a[i] != '']

建议使用re.escape以避免正则表达式中的无效符号。

Answer 3

你可以使用

import re
a = ["%!It depends%% on what you m\ean by dying.",
     "It is widely~ read and at the top_x000D_ of all the search%%__ engines.",
     "\H~owever, Wikipedia has internal problems",
     "%%a+b!=a-b"]
pattern = re.compile(r'%!|_x000D_|__|[~%\]')
p = [pattern.sub('', item) for item in a if item]
print(p)

产生

['It depends on what you mean by dying.', 
 'It is widely read and at the top of all the search engines.',
 'However, Wikipedia has internal problems', 
 'a+b!=a-b']

记得把较长的替换放在交替的左边。

我们可以多次使用 re.sub 而不是使用 str.replace

Can we use re.sub instead of using str.replace many time

python

python-re