我如何以不同的方式使用 CASE?
How I can use CASE in a different way?
您好,我正在尝试构建一个项目,但 case '2'
无法正常工作。
struct student
{
string fname;//for student first name
string lname;//for student last name
string id;//for Registration No number
string course;//for class info
}studentData;//Variable of student type
struct teacher
{
string fname;//first name of teacher
string lname;//last name of teacher
string id;//Bool Group
string course;//Number of serves in School
}teach;//Variable of teacher type
int main()
{
int i = 0, j;//for processing usage
char choice;//for getting choice
string find;//for sorting
string srch;
while (1)//outer loop
{
system("cls");//Clear screen
//Level 1-Display process
cout << "\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\";
cout << "\n\n\t\t\tSCHOOL MANAGEMENT PROGRAM\n\n";
cout << "\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\";
cout << "\n\n\t\t\tMAIN SCREEN\n\n";
cout << "Enter your choice: " << endl;
cout << "1.Students information" << endl;
cout << "2.Teacher information" << endl;
cout << "3. Course information " << endl;
cout << "4. Display Strudent information " << endl;
cout << "5. Display Teacher Information " << endl;
cout << "6. Display Course Information n" << endl;
cout << "7.Exit program" << endl;
cin >> choice;
system("cls");//Clear screen
switch (choice)//First switch
{
case '1': //Student
{
{ ofstream f1("student.txt", ios::app);
for (i = 0; choice != 'n'; i++)
{
if ((choice == 'y') || (choice == 'Y') || (choice == '1'))
{
cout << "Enter First name: ";
cin >> studentData.fname;
cout << "Enter Last name: ";
cin >> studentData.lname;
cout << "Enter Registration number: ";
cin >> studentData.id;
cout << "Enter class: ";
cin >> studentData.course;
f1 << studentData.fname << endl << studentData.lname << endl << studentData.id << endl << studentData.course << endl;
cout << "Do you want to enter data: ";
cout << "Press Y for Continue and N to Finish: ";
cin >> choice;
}
}
f1.close();
}
continue;//control back to inner loop -1
continue;//Control pass to 1st loop
}
case '2'://Teachers biodata
{
{ ofstream t1("teacher.txt", ios::app);
for (i = 0; choice != 'n'; i++)
{
if ((choice == 'y') || (choice == 'Y') || (choice == '1'))
{
cout << "Enter First name: ";
cin >> teach.fname;
cout << "Enter Last name: ";
cin >> teach.lname;
cout << "Enter Registration number: ";
cin >> teach.id;
cout << "Enter class: ";
cin >> teach.course;
t1 << teach.fname << endl << teach.lname << endl << teach.id << endl << teach.course << endl;
cout << "Do you want to enter data: ";
cout << "Press Y for Continue and N to Finish: ";
cin >> choice;
}
}
t1.close();
continue;//control back to inner loop -1
}
continue;//Control pass to 1st loop
}
case '3':
{
{ ifstream f2("student.txt");
cout << "Enter First name to be displayed: ";
cin >> find;
cout << endl;
int notFound = 0;
for (j = 0; (j < i) || (!f2.eof()); j++)
{
getline(f2, studentData.fname);
if (studentData.fname == find)
{
notFound = 1;
cout << "First Name: " << studentData.fname << endl;
cout << "Last Name: " << studentData.lname << endl;
getline(f2, studentData.id);
cout << "Registration No number: " << studentData.id << endl;
getline(f2, studentData.course);
cout << "Class: " << studentData.course << endl << endl;
}
}
if (notFound == 0) {
cout << "No Record Found" << endl;
}
f2.close();
cout << "Press any key two times to proceed";
_getch();//To hold data on screen
_getch();//To hold data on screen
}
continue;//control back to inner loop -1
}
case '4':
{
{ ifstream t2("teacher.txt");
cout << "Enter First name to be displayed: ";
cin >> find;
cout << endl;
int notFound = 0;
for (j = 0; (j < i) || (!t2.eof()); j++)
{
getline(t2, studentData.fname);
if (studentData.fname == find)
{
notFound = 1;
cout << "First Name: " << studentData.fname << endl;
cout << "Last Name: " << studentData.lname << endl;
getline(t2, teach.id);
cout << "Registration No number: " << studentData.id << endl;
getline(t2, teach.course);
cout << "Class: " << studentData.course << endl << endl;
}
}
if (notFound == 0) {
cout << "No Record Found" << endl;
}
t2.close();
cout << "Press any key two times to proceed";
_getch();//To hold data on screen
_getch();//To hold data on screen
}
continue;//control back to inner loop -1
}
case '5':
{}
case '6':
{}
case '7':
{
break;//outer case 3
}//outer case 3
break;//outer loop
}
}
}
在您的 switch 语句中,在您检查 "choice" 是否为 '2 (case '2'://Teachers biodata
) 的情况下,您还有另一个 if 语句检查 "choice" 是否为 ' 1',但此时 "choice" 将是 '2'。
if ((choice == 'y') || (choice == 'Y') || (choice == '1'))
变成
if ((choice == 'y') || (choice == 'Y') || (choice == '2'))
您好,我正在尝试构建一个项目,但 case '2'
无法正常工作。
struct student
{
string fname;//for student first name
string lname;//for student last name
string id;//for Registration No number
string course;//for class info
}studentData;//Variable of student type
struct teacher
{
string fname;//first name of teacher
string lname;//last name of teacher
string id;//Bool Group
string course;//Number of serves in School
}teach;//Variable of teacher type
int main()
{
int i = 0, j;//for processing usage
char choice;//for getting choice
string find;//for sorting
string srch;
while (1)//outer loop
{
system("cls");//Clear screen
//Level 1-Display process
cout << "\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\";
cout << "\n\n\t\t\tSCHOOL MANAGEMENT PROGRAM\n\n";
cout << "\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\";
cout << "\n\n\t\t\tMAIN SCREEN\n\n";
cout << "Enter your choice: " << endl;
cout << "1.Students information" << endl;
cout << "2.Teacher information" << endl;
cout << "3. Course information " << endl;
cout << "4. Display Strudent information " << endl;
cout << "5. Display Teacher Information " << endl;
cout << "6. Display Course Information n" << endl;
cout << "7.Exit program" << endl;
cin >> choice;
system("cls");//Clear screen
switch (choice)//First switch
{
case '1': //Student
{
{ ofstream f1("student.txt", ios::app);
for (i = 0; choice != 'n'; i++)
{
if ((choice == 'y') || (choice == 'Y') || (choice == '1'))
{
cout << "Enter First name: ";
cin >> studentData.fname;
cout << "Enter Last name: ";
cin >> studentData.lname;
cout << "Enter Registration number: ";
cin >> studentData.id;
cout << "Enter class: ";
cin >> studentData.course;
f1 << studentData.fname << endl << studentData.lname << endl << studentData.id << endl << studentData.course << endl;
cout << "Do you want to enter data: ";
cout << "Press Y for Continue and N to Finish: ";
cin >> choice;
}
}
f1.close();
}
continue;//control back to inner loop -1
continue;//Control pass to 1st loop
}
case '2'://Teachers biodata
{
{ ofstream t1("teacher.txt", ios::app);
for (i = 0; choice != 'n'; i++)
{
if ((choice == 'y') || (choice == 'Y') || (choice == '1'))
{
cout << "Enter First name: ";
cin >> teach.fname;
cout << "Enter Last name: ";
cin >> teach.lname;
cout << "Enter Registration number: ";
cin >> teach.id;
cout << "Enter class: ";
cin >> teach.course;
t1 << teach.fname << endl << teach.lname << endl << teach.id << endl << teach.course << endl;
cout << "Do you want to enter data: ";
cout << "Press Y for Continue and N to Finish: ";
cin >> choice;
}
}
t1.close();
continue;//control back to inner loop -1
}
continue;//Control pass to 1st loop
}
case '3':
{
{ ifstream f2("student.txt");
cout << "Enter First name to be displayed: ";
cin >> find;
cout << endl;
int notFound = 0;
for (j = 0; (j < i) || (!f2.eof()); j++)
{
getline(f2, studentData.fname);
if (studentData.fname == find)
{
notFound = 1;
cout << "First Name: " << studentData.fname << endl;
cout << "Last Name: " << studentData.lname << endl;
getline(f2, studentData.id);
cout << "Registration No number: " << studentData.id << endl;
getline(f2, studentData.course);
cout << "Class: " << studentData.course << endl << endl;
}
}
if (notFound == 0) {
cout << "No Record Found" << endl;
}
f2.close();
cout << "Press any key two times to proceed";
_getch();//To hold data on screen
_getch();//To hold data on screen
}
continue;//control back to inner loop -1
}
case '4':
{
{ ifstream t2("teacher.txt");
cout << "Enter First name to be displayed: ";
cin >> find;
cout << endl;
int notFound = 0;
for (j = 0; (j < i) || (!t2.eof()); j++)
{
getline(t2, studentData.fname);
if (studentData.fname == find)
{
notFound = 1;
cout << "First Name: " << studentData.fname << endl;
cout << "Last Name: " << studentData.lname << endl;
getline(t2, teach.id);
cout << "Registration No number: " << studentData.id << endl;
getline(t2, teach.course);
cout << "Class: " << studentData.course << endl << endl;
}
}
if (notFound == 0) {
cout << "No Record Found" << endl;
}
t2.close();
cout << "Press any key two times to proceed";
_getch();//To hold data on screen
_getch();//To hold data on screen
}
continue;//control back to inner loop -1
}
case '5':
{}
case '6':
{}
case '7':
{
break;//outer case 3
}//outer case 3
break;//outer loop
}
}
}
在您的 switch 语句中,在您检查 "choice" 是否为 '2 (case '2'://Teachers biodata
) 的情况下,您还有另一个 if 语句检查 "choice" 是否为 ' 1',但此时 "choice" 将是 '2'。
if ((choice == 'y') || (choice == 'Y') || (choice == '1'))
变成
if ((choice == 'y') || (choice == 'Y') || (choice == '2'))