将 setInterval 转换为 promise
Convert setInterval to promise
你好,我是 javascript 的新手,想知道是否有办法将低于 setInterval 的东西转换成一个 promise,以便可以使用 .then
而不是 callback
。有帮助吗?
我的想法:
使用 setTimeout
我可以在固定时间后 resolve
。但我对 setInterval
没有任何想法......
function alert_above(scrip, price, callback) {
var intvl = setInterval(() => {
if (get_last_price(scrip) > price) {
callback();
clearInterval(intvl);
}
}, 1000);
return intvl;
}
我想你可以包装成一个 new Promise
像 :
function promisifySetInterval(time) {
var defer = new Promise(resolve => {
let counter = 0
var intvl = setInterval(() => {
if (counter > time) {
resolve('hey');
clearInterval(intvl);
} else {
counter += 1000
}
}, 1000);
})
return defer;
}
promisifySetInterval(2000).then(param => {
console.log('hey', param)
})
对于你这样的情况:
function alert_above(scrip, price) {
var defer = new Promise(resolve => {
var intvl = setInterval(() => {
if (get_last_price(scrip) > price) {
resolve('hey');
clearInterval(intvl);
}
}, 1000);
})
return defer;
}
alert_above().then(param => {
console.log('hey', param)
})
您可以创建异步解析的承诺函数。详细了解 Promise Here
function myInterval() {
return new Promise(resolve => {
const intId = setInterval(() => {
clearInterval(intId);
resolve();
}, 1000)
})
}
myInterval().then(() => {
console.log('Called after 1 second');
})
注意:poll
会在第一次执行时不延迟,与原生的setInterval
不同。
问:为什么 poll
基于 setTimeout
而不是 setInterval
?
答:请参阅 Execute the setInterval function without delay the first time。
实施:
// Promisify setTimeout
const pause = (ms, cb, ...args) =>
new Promise((resolve, reject) => {
setTimeout(async () => {
try {
resolve(await cb?.(...args))
} catch (error) {
reject(error)
}
}, ms)
})
// Promisify setInterval
const poll = async (interval, times, cb, ...args) => {
let result
const resolve = value => (times = 0) || (result = value)
const reject = reason => (times = 0) || (result = Promise.reject(reason))
await (async function basePoll() {
if (times > 0) {
const _result = await cb(...args, resolve, reject)
if (times) {
result = _result
--times && (await pause(interval, basePoll))
}
}
})()
return result
}
测试:
import ordinal from 'ordinal'
// Test 1
poll(1000, 3, (a, b, c) => [a, b, c], 1, 2, 3).then(value => console.log(value))
// Test 2
let times = 0
poll(1000, 5, resolve => {
console.log(`${ordinal(++times)} time`)
times === 3 && resolve('resolved')
}).then(value => console.log(value))
// Test 3
let times = 0
poll(1000, 5, (resolve, reject) => {
console.log(`${ordinal(++times)} time`)
times === 3 && reject('rejected')
}).catch(error => console.error(error))
你好,我是 javascript 的新手,想知道是否有办法将低于 setInterval 的东西转换成一个 promise,以便可以使用 .then
而不是 callback
。有帮助吗?
我的想法:
使用 setTimeout
我可以在固定时间后 resolve
。但我对 setInterval
没有任何想法......
function alert_above(scrip, price, callback) {
var intvl = setInterval(() => {
if (get_last_price(scrip) > price) {
callback();
clearInterval(intvl);
}
}, 1000);
return intvl;
}
我想你可以包装成一个 new Promise
像 :
function promisifySetInterval(time) {
var defer = new Promise(resolve => {
let counter = 0
var intvl = setInterval(() => {
if (counter > time) {
resolve('hey');
clearInterval(intvl);
} else {
counter += 1000
}
}, 1000);
})
return defer;
}
promisifySetInterval(2000).then(param => {
console.log('hey', param)
})
对于你这样的情况:
function alert_above(scrip, price) {
var defer = new Promise(resolve => {
var intvl = setInterval(() => {
if (get_last_price(scrip) > price) {
resolve('hey');
clearInterval(intvl);
}
}, 1000);
})
return defer;
}
alert_above().then(param => {
console.log('hey', param)
})
您可以创建异步解析的承诺函数。详细了解 Promise Here
function myInterval() {
return new Promise(resolve => {
const intId = setInterval(() => {
clearInterval(intId);
resolve();
}, 1000)
})
}
myInterval().then(() => {
console.log('Called after 1 second');
})
注意:poll
会在第一次执行时不延迟,与原生的setInterval
不同。
问:为什么 poll
基于 setTimeout
而不是 setInterval
?
答:请参阅 Execute the setInterval function without delay the first time。
实施:
// Promisify setTimeout
const pause = (ms, cb, ...args) =>
new Promise((resolve, reject) => {
setTimeout(async () => {
try {
resolve(await cb?.(...args))
} catch (error) {
reject(error)
}
}, ms)
})
// Promisify setInterval
const poll = async (interval, times, cb, ...args) => {
let result
const resolve = value => (times = 0) || (result = value)
const reject = reason => (times = 0) || (result = Promise.reject(reason))
await (async function basePoll() {
if (times > 0) {
const _result = await cb(...args, resolve, reject)
if (times) {
result = _result
--times && (await pause(interval, basePoll))
}
}
})()
return result
}
测试:
import ordinal from 'ordinal'
// Test 1
poll(1000, 3, (a, b, c) => [a, b, c], 1, 2, 3).then(value => console.log(value))
// Test 2
let times = 0
poll(1000, 5, resolve => {
console.log(`${ordinal(++times)} time`)
times === 3 && resolve('resolved')
}).then(value => console.log(value))
// Test 3
let times = 0
poll(1000, 5, (resolve, reject) => {
console.log(`${ordinal(++times)} time`)
times === 3 && reject('rejected')
}).catch(error => console.error(error))