隐式移动构造函数

Question

隐式移动构造函数到底在做什么？例如，对于以下 class，隐式移动构造函数会是什么样子（您能否提供此隐式构造函数的一些示例实现）：

struct A
{
    A()           = default;
    A(A && other) = default;
    int a;
};

struct B : public A
{
    int b;
    int * c;
};

实现会像这样吗：

B(B && other) : A(std::move(other)), b(std::move(other.b)), c(std::move(other.c)) {}

Answer 1

来自cppreference.com：

For union types, the implicitly-defined move constructor copies the object representation (as by std::memmove). For non-union class types (class and struct), the move constructor performs full member-wise move of the object's bases and non-static members, in their initialization order, using direct initialization with an xvalue argument. If this satisfies the requirements of a constexpr constructor, the generated move constructor is constexpr.

基础 class 构造函数在派生构造函数之前运行。

隐式移动构造函数

Implicit move constructor

c++

move-semantics

c++11