如何根据单个 table 中的数据计算 2 个特定时期的收入差异？

Question

我正在使用 SQL Server 2014，我有以下 T-SQL 查询，它应该根据 2 个特定时期计算总收入的差异。执行计算的数据来自单个 SQL Table.

总而言之，我在 table T1 中有一个名为 Revenue 的专栏和另一个名为 Month 的专栏。我需要找出 2020 年 9 月至 2020 年 12 月与 2019 年 9 月至 2019 年 12 月的收入差异。

我的T-SQL查询如下：

USE [MyDatabase]

;with cte1 as 
(
  SELECT 
    sum ([Revenue]) as 'Revenue Sep 19 - Dec 19'
  FROM
    [T1]
  WHERE
    [Month] between '2019-09-01' and '2019-12-01'
),
cte2 as (
  SELECT
    sum ([Revenue]) as 'Revenue Sep 20 - Dec 20'
  FROM
    [T1]
  WHERE
    [Month] between '2020-09-01' and '2020-12-01'
),
cte3 as (
  SELECT 
    cte2.[Revenue Sep 20 - Dec 20] as 'Total Revenue',
    'Sep 20 - Dec 20' as 'Period',
    '1' as 'ID'
  FROM
    [cte2]

  UNION ALL 

  SELECT 
    cte1.[Revenue Sep 19 - Dec 19] as 'Total Revenue',
    'Sep 19 - Dec 19' as 'Period',
    '1' as 'ID'
  FROM
    [cte1]
)
select a.[Total Revenue] - b.[Total Revenue]
from
  (select cte3.[Total Revenue] from [cte3] where cte3.[Period] = 'Sep 20 - Dec 20') a
  JOIN
  (select cte3.[Total Revenue] from [cte3] where cte3.[Period] = 'Sep 19 - Dec 19') b
  ON b.[ID] = a.[ID]

我的查询基于以下内容：How to calculate between different group of rows of the same table

但是，当运行我的查询时，我收到以下错误消息：

Invalid column name 'ID'.

我不知道我做错了什么。 cte3 中不存在第 ID 列吗？

Answer 1

ID 必须出现在 a 和 b 的 select 列表中才能对 join:

from
  (select cte3.ID, cte3.[Total Revenue] from [cte3] where cte3.[Period] = 'Sep 20 - Dec 20') a
  JOIN
  (select cte3.ID, cte3.[Total Revenue] from [cte3] where cte3.[Period] = 'Sep 19 - Dec 19') b
  ON b.[ID] = a.[ID]

Answer 2

在使用 SUB QUERY 时，您还必须提及在 Join 条件中提及的列

SELECT A.[TOTAL REVENUE] - B.[TOTAL REVENUE]
FROM
(SELECT CTE3.[TOTAL REVENUE],CTE3.ID FROM [CTE3] WHERE CTE3.[PERIOD] = 'SEP 20 - DEC 20') A
JOIN
(SELECT CTE3.[TOTAL REVENUE],CTE3.ID FROM [CTE3] WHERE CTE3.[PERIOD] = 'SEP 19 - DEC 19') B ON B.[ID] = A.[ID]

Answer 3

试试下面的代码，它会对你有所帮助

USE [MyDatabase]

select sum([Revenue Sep 20 - Dec 20])-sum([Revenue Sep 19 - Dec 19]) as revenue_diffrence 
from
(
SELECT 
    [Revenue] as 'Revenue Sep 19 - Dec 19', 0 as 'Revenue Sep 20 - Dec 20'
  FROM
    [T1]
  WHERE
    [Month] between '2019-09-01' and '2019-12-01'

union all
SELECT
    0 as 'Revenue Sep 19 - Dec 19',[Revenue] as 'Revenue Sep 20 - Dec 20'
  FROM
    [T1]
  WHERE
    [Month] between '2020-09-01' and '2020-12-01'
)a

Answer 4

您的查询比必要的复杂得多。

SELECT (SUM(CASE WHEN [Month] between '2020-09-01' and '2020-12-01' THEN [Revenue] ELSE 0 END) -
        SUM(CASE WHEN [Month] between '2019-09-01' and '2019-12-01' THEN [Revenue] ELSE 0 END)
       ) as difference
FROM [T1];

您的版本具有三个 CTE、一个 UNION ALL、两个子查询和一个 JOIN。

备注：

不要使用单引号来分隔列别名。仅对字符串和日期使用单引号。
命名您的列别名，这样它们就不需要转义了。例如，使用下划线代替空格。
不要使用无意义的 table 别名，例如 a 和 b。使用有意义的，例如 t2019.

如何根据单个 table 中的数据计算 2 个特定时期的收入差异？

How to calculate the difference in revenue for 2 specific periods from data in a single table?

sql

tsql

sql-server

sql-server-2014