我如何在 python 中一次检查两个到套接字的连接

Question

我正在运行ning 一个 python 脚本来侦听与我的计算机的传入连接。我正在监听两个端口 9999 和 9998。但是，当我使用 .accept() 检查与我的第一个端口的连接时，它会一直等待，直到我连接到运行下面的代码意味着我的另一个端口可以检查用于连接。

我希望能够同时检查连接并运行根据已连接的端口进行编码，这是我当前的代码。

import socket
import subprocess
import os


while 1 > 0:
# Set connection for C_shutdown script on port 9999
    HOST = '192.168.1.46' 
    PORT = 9999
    server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    server_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
    server_socket.bind((HOST, PORT))
    server_socket.listen(10)
    print("Listening for Shutdown connection")

# Set connection for Light_on script on port 9998
    HOST = '192.168.1.46' 
    PORT2 = 9998
    light_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    light_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
    light_socket.bind((HOST, PORT2))
    light_socket.listen(10)
    print("Listening for Light Connection")

    l = light_socket.accept()
    print("Light script connected")


    s = server_socket.accept()
    print("Shutdown Script Connected")

Answer 1

每个服务器都应该运行在其单独的线程中，如下所示：

# ... other imports ...
import threading

def server_job():
    # ... Code for server_socket ...
    print("Listening for server connection")
    while True:
        s = server_socket.accept()
        # ... Anything you want to do with s ...

def light_job():
    # ... Code for light_socket ...
    print("Listening for Light Connection")
    while True:
        l = light_socket.accept()
        # ... Anything you want to do with l ...

# Creates Thread instances that will run both server_job and light_job
t_server = threading.Thread(target=server_job)
t_light = threading.Thread(target=light_job)

# Begin their execution
t_server.start()
t_light.start()

# Wait for both threads to finish their execution
t_light.join()
t_server.join()

这里每个线程都有它的 while True 循环来接受多个连接，绑定和监听一个端口应该只发生一次。

其他选项是生成两个进程而不是两个线程，但这取决于您的用例，例如，如果您不需要在这些线程之间共享数据并且想要 GIL. In that case, might want to take a look at https://docs.python.org/3/library/multiprocessing.html[ 的解决方法=12=]

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