Expression.Lambda 具有多个输入选择器

Question

我正在尝试创建我自己的自定义操作，我可以在数据库中使用它来查找受值更改影响的行。

我正在查看运算符示例之间的 Jon Skeets：LINQ Between Operator 但我遇到了麻烦，因为我的操作包含多个参数输入

    public static IQueryable<TSource> LeavingRange<TSource, TKey>(this IQueryable<TSource> source,
        Expression<Func<TSource, TKey>> lowKeySelector,
        Expression<Func<TSource, TKey>> highKeySelector,
        Nullable<TKey> oldValue,
        Nullable<TKey> newValue)
            where TKey : struct, IComparable<TKey>

如您所见，我有 2 个选择器，但我不太确定如何将它们正确组合到 Expression.Lambda 调用的参数中。我试过将两个输入表达式的参数作为参数放入 lambda 中，但我认为我遗漏了一些东西。

Expression.Lambda<Func<TSource, bool>>(isLeavingRange, lowKeySelector.Parameters[0], highKeySelector.Parameters[0]);

这样做会出现以下错误：

Incorrect number of parameters supplied for lambda declaration

构造Lambda时输入参数的正确组合方式是什么？

支持信息

我的完整代码在下面，但我认为相关位是两个选择器和 Expression.Lambda 调用

    public static IQueryable<TSource> LeavingRange<TSource, TKey>(this IQueryable<TSource> source,
        Expression<Func<TSource, TKey>> lowKeySelector,
        Expression<Func<TSource, TKey>> highKeySelector,
        Nullable<TKey> oldValue,
        Nullable<TKey> newValue)
            where TKey : struct, IComparable<TKey>
    {
        Expression lowKey = Expression.Invoke(lowKeySelector, lowKeySelector.Parameters.ToArray());
        Expression highKey = Expression.Invoke(highKeySelector, highKeySelector.Parameters.ToArray());

        //is oldValue null which means it cant possibly be leaving
        var oldValueIsNotNull = Expression.NotEqual(Expression.Constant(oldValue, typeof(Nullable<TKey>)), Expression.Constant(null, typeof(Nullable<TKey>)));
        var newValueIsNull = Expression.Equal(Expression.Constant(newValue, typeof(Nullable<TKey>)), Expression.Constant(null, typeof(Nullable<TKey>)));
        var newValueIsNotNull = Expression.Not(newValueIsNull);

        var oldValueIsBetweenRange = Between(Expression.Convert(Expression.Constant(oldValue), typeof(TKey)), lowKey, highKey);
        var newValueIsNotBetweenRange = Expression.Not(Between(Expression.Convert(Expression.Constant(newValue), typeof(TKey)), lowKey, highKey));

        //IE leaving because its going from in the range to null
        var newValueIsNullAndOldValueIsBetweenRange = Expression.AndAlso(newValueIsNull, oldValueIsBetweenRange);

        var oldValueIsInRangeAndNewValueIsNot = Expression.AndAlso(newValueIsNotNull, Expression.AndAlso(oldValueIsBetweenRange, newValueIsNotBetweenRange));
        var isLeavingRange = Expression.AndAlso(oldValueIsNotNull, Expression.Or(newValueIsNullAndOldValueIsBetweenRange, oldValueIsInRangeAndNewValueIsNot));

        var leavingRange = Expression.Lambda<Func<TSource, bool>>(isLeavingRange, lowKeySelector.Parameters[0], highKeySelector.Parameters[0]);
        
        return source.Where(leavingRange);
    }

Answer 1

传递给 Where() 的委托只将集合中的每个元素作为参数，所以你需要使调用 lowKeySelector 和 highKeySelector 的两个表达式采用相同的元素（ParameterExpression 的相同实例）作为参数并且还需要构建 lambda 表达式以将其用作参数。

public static IQueryable<TSource> LeavingRange<TSource, TKey>(this IQueryable<TSource> source,
     Expression<Func<TSource, TKey>> lowKeySelector,
     Expression<Func<TSource, TKey>> highKeySelector,
     Nullable<TKey> oldValue,
     Nullable<TKey> newValue)
         where TKey : struct, IComparable<TKey>
{
    ParameterExpression paramOfWhereDelg = Expression.Parameter(typeof(TSource), "p");

    Expression lowKey = Expression.Invoke(lowKeySelector, paramOfWhereDelg);
    Expression highKey = Expression.Invoke(highKeySelector, paramOfWhereDelg);

    // Build your expression tree
    //  ...

    var leavingRange = Expression.Lambda<Func<TSource, bool>>(isLeavingRange, paramOfWhereDelg);

    return source.Where(leavingRange);
}

（或者您可以使用 lowKeySelector.Parameters 而不是 paramOfWhereDelg，但我相信创建另一个 ParameterExpression 会更容易理解。）

Expression.Lambda 具有多个输入选择器

Expression.Lambda with multiple input selectors

c#

linq

lambda

支持信息