SELECT 在 SQL 中按周分组的数据

Question

我有一个有效的查询 (ORACLE SQL)，它给我按商店编号分组的加仑数，以及按类型和百分比列汇总的加仑数。每个商店编号都有不同的转换日期，我从中总结数据 -

SELECT StoreNbr, 
SUM(CASE WHEN(ClrntSys IN ('844', '84448')) THEN Gallons ELSE 0 END) AS Gallons_844,
SUM(CASE WHEN(ClrntSys ='GIC') THEN Gallons ELSE 0 END) AS Gallons_GIC,
SUM(CASE WHEN(ClrntSys IN ('844', '84448', 'GIC')) THEN Gallons ELSE 0 END) AS Total_Gallons,
CONCAT(CAST((SUM(CASE WHEN(ClrntSys ='GIC') THEN Gallons ELSE 0 END) /
SUM(CASE WHEN(ClrntSys IN ('844', '84448', 'GIC')) THEN Gallons ELSE 0 END)) AS DECIMAL (5,2)) * 100, '%') AS Percent_GIC
FROM MQ_CDS_NETTRAN
WHERE ClrntSys IN ('844', '84448', 'GIC')
AND ((CostCenter = '701104' AND LastTranDate >= DATE '2020-03-10') 
OR (CostCenter = '701109' AND LastTranDate >= DATE '2020-03-04')
OR (CostCenter = '701257' AND LastTranDate >= DATE '2020-03-12'))
GROUP BY StoreNbr
ORDER BY StoreNbr;

我现在还需要按周汇总，星期日是每周的第一天，但我无法理解 DATEPART 的工作原理。为了得到一个更好的主意，我只尝试使用我在网上看到的 DATEPART 示例来总结上周的数据，但这不起作用。它给了我 "invalid identifier DATEPART"。 -

SELECT DATEPART(week, 5/17/20) AS weekTotal, 
StoreNbr, 
SUM(CASE WHEN(ClrntSys IN ('844', '84448')) THEN Gallons ELSE 0 END) AS Gallons_844,
SUM(CASE WHEN(ClrntSys ='GIC') THEN Gallons ELSE 0 END) AS Gallons_GIC,
SUM(CASE WHEN(ClrntSys IN ('844', '84448', 'GIC')) THEN Gallons ELSE 0 END) AS Total_Gallons,
CONCAT(CAST((SUM(CASE WHEN(ClrntSys ='GIC') THEN Gallons ELSE 0 END) /
SUM(CASE WHEN(ClrntSys IN ('844', '84448', 'GIC')) THEN Gallons ELSE 0 END)) AS DECIMAL (5,2)) * 100, '%') AS Percent_GIC
FROM MQ_CDS_NETTRAN
WHERE ((CostCenter = '701104' AND LastTranDate >= DATE '2020-03-10') 
OR (CostCenter = '701109' AND LastTranDate >= DATE '2020-03-04')
OR (CostCenter = '701257' AND LastTranDate >= DATE '2020-03-12'))
GROUP BY DATEPART(week, 5/17/20), StoreNbr
ORDER BY StoreNbr;

然而，我真正需要的是每周的数据（星期日是每周的开始）分别汇总到每个商店的转化日期。有可能这样做吗？除了 DATEPART 之外，还有其他更好的东西吗？

Answer 1

抱歉 - 刚刚注意到您说的是 Oracle SQL，而我的第一个答案是 SQL 服务器！您收到错误的原因是 DATEPART 不是 Oracle 函数。相反，您可以简单地对日期进行数学计算，使用已知的星期日（在数据库中已知的第一个日期 table 之前）作为锚定日期：

SELECT
    '30-DEC-2018' as "Known Sunday,
    trunc((sysdate - to_date('30-DEC-2018')) / 7) as "Week Num",
    to_date('30-DEC-2018') 
        + (trunc((sysdate - to_date('30-DEC-2018')) / 7) * 7)"
FROM
    dual

SELECT 在 SQL 中按周分组的数据

SELECT data grouped by WEEK in SQL

sql

oracle

datepart