将一些行值透视到列

Question

我正在尝试将一些行值转换为一列，下面是我要实现的目标。

我当前的架构：

+------+----------+
|  ID  |   name   |
+------+----------+
|   01 |  Vsp lan |
| 0121 |  abn     |
| 0122 |  abb     |
| 0123 |  vsp     |
|   02 |  Apn lan |
| 0211 |  add     |
| 0221 |  acd     |
+------+----------+

这就是我想要实现的目标：

+-----+--------+-------+---------+
| kod |   ID   | name  |   lan   |
+-----+--------+-------+---------+
|  01 |   0121 |   abn | vsp lan |
|  01 |   0122 |   abb | vsp lan |
|  01 |   0123 |   vsp | vsp lan |
|  02 |   0211 |   add | Apn lan |
|  02 |   0221 |   acd | Apn lan |
+-----+--------+-------+---------+

但是当 name 和 lan 具有相似的值时它会跳过行，在这种情况下它会跳过名称值为 vsp 的行。

DECLARE @table TABLE (ID VARCHAR(5),[name] VARCHAR(10));
INSERT INTO @table
VALUES
 ('01','Vsp Ian')
,('0121','abn')
,('0122','abb')
,('0123','vsp')

,('02','Apn Ian')
,('0211','add')
,('0221','acd')
;

SELECT a.id as kod, b.id as ID, B.name as name, a.name as lan
FROM @table a
inner join @table b on CHARINDEX(a.id,b.id) = 1 and CHARINDEX(b.name,a.name) = 0

Answer 1

我能想到的直接方法是自连接，其中一个 ID 从另一个开始

SELECT a.id as kod, b.id as ID, B.name as name, a.name as laen
FROM table_name a
inner join table_name b on CHARINDEX(a.name,b.name) = 1 and CHARINDEX(b.name,a.name) = 0

这应该适用于您的示例，但如果 ID 也更长，结果可能会很奇怪

Answer 2

我正在观察 ID 值的模式。例如，ID 0121, 0122 可以归类为 ID 01。同样，ID 0211, 0221 可以归类为 ID 02。基于这个假设，这个查询应该做：

select 
    tb1.ID as kod, 
    tb2.ID as ID, 
    tb2.name as name, 
    tb1.name as laen 
from tableName tb1 join tableName tb2 
on tb1.ID != tb2.ID and LOCATE(tb1.ID,tb2.ID) = 1

Answer 3

根据您的示例，如果 van_ian kod 是名称 ID 的开头，我假设您想将 Van_ian 映射到其他名称。例如，01 是 0121、0122 的开始。

DECLARE @table table(id CHAR(10), name varchar(10))

INSERT INTO @table
values
('01','vsp ian'),
('0121','abn'),
('0122','abb'),
('02','vsp ian'),
('0211','add'),
('0221','acd');

SELECT ct.id as kod,ot.id, ot.name,ct.name as ian FROM @table as ot
CROSS JOIN
(SELECT distinct id, name from @table WHERE name like 'vsp%'
) as ct(id,name)
WHERE ot.name not like 'vsp%'
and LEFT(ot.id,2) = ct.id

+-----+--------+-------+---------+
| kod |   id   | name  |   ian   |
+-----+--------+-------+---------+
|  01 |   0121 |   abn | vsp ian |
|  01 |   0122 |   abb | vsp ian |
|  02 |   0211 |   add | vsp ian |
|  02 |   0221 |   acd | vsp ian |
+-----+--------+-------+---------+

Answer 4

Venkataraman R 你的答案非常接近，我稍微调整了一下以匹配他的输出。

DECLARE @table TABLE (ID VARCHAR(5),[name] VARCHAR(10));
INSERT INTO @table
VALUES
 ('01','Vsp_Ian')
,('0121','abn')
,('0122','abb')
,('02','Apn_Ian')
,('0211','add')
,('0221','acd')
,('03','Ubb_Ian')
,('0301','afg')
,('0302','ampx');

SELECT
 kod = ct.id
,ot.ID
,ot.[name]
,Ian = ct.[name]
FROM @table ot
CROSS JOIN (SELECT ID,[name] FROM @table WHERE [name] LIKE '%[_]%') ct
WHERE ot.[name] NOT LIKE '%[_]%'
AND LEFT(ot.id,2) = ct.id;

Answer 5

这解决了我的问题。

DECLARE @table TABLE (ID VARCHAR(5),[name] VARCHAR(10));
INSERT INTO @table
VALUES
 ('01','Vsp Ian')
,('0121','abn')
,('0122','abb')
,('0123','vsp')
,('02','Apn Ian')
,('0211','add')
,('0221','acd')
,('03','Ubb Ian')
,('0301','afg')
,('0302','ampx');


SELECT
 kod = ct.id
,ot.ID
,ot.[name]
,Ian = ct.[name]
FROM @table ot
CROSS JOIN (SELECT ID,[name] FROM @table WHERE [name] LIKE '%[lan]%') ct
WHERE len(ot.ID) > 2 
AND LEFT(ot.id,2) = ct.id;

将一些行值透视到列

Pivot some row values to a columns

sql

sql-server

ssis-2012