如果文件已经存在,如何防止 shutil.move 覆盖该文件?
How to prevent shutil.move from overwriting a file if it already exists?
我在 Windows
中使用此 Python
代码:
shutil.move(documents_dir + "\" + file_name, documents_dir + "\backup\"
+ subdir_name + "\" + file_name)
当此代码被多次调用时,它会覆盖目标文件。我想移动文件
如果目的地已经存在,重命名它
例如file_name
= foo.pdf
并且在 backup
文件夹中将是 foo.pdf
、foo(1).pdf
、foo(2).pdf
等或类似的,例如带破折号
foo-1.pdf
、foo-2.pdf
等
您可以边走边查看 os.path.exists()
。
import os
import shutil
file_name = 'test.csv'
documents_dir = r'C:\BR\Test'
subdir_name = 'test'
# using os.path.join() makes your code easier to port to another OS
source = os.path.join(documents_dir, file_name)
dest = os.path.join(documents_dir, 'backup', subdir_name, file_name)
num = 0
# loop until we find a file that doesn't exist
while os.path.exists(dest):
num += 1
# use rfind to find your file extension if there is one
period = file_name.rfind('.')
# this ensures that it will work with files without extensions
if period == -1:
period = len(file_name)
# create our new destination
# we could extract the number and increment it
# but this allows us to fill in the gaps if there are any
# it has the added benefit of avoiding errors
# in file names like this "test(sometext).pdf"
new_file = f'{file_name[:period]}({num}){file_name[period:]}'
dest = os.path.join(documents_dir, 'backup', subdir_name, new_file)
shutil.move(source, dest)
或者由于这可能在循环中使用,您可以将其放入函数中。
import os
import shutil
def get_next_file(file_name, dest_dir):
dest = os.path.join(dest_dir, file_name)
num = 0
while os.path.exists(dest):
num += 1
period = file_name.rfind('.')
if period == -1:
period = len(file_name)
new_file = f'{file_name[:period]}({num}){file_name[period:]}'
dest = os.path.join(dest_dir, new_file)
return dest
file_name = 'test.csv'
documents_dir = r'C:\BR\Test'
subdir_name = 'test'
source = os.path.join(documents_dir, file_name)
dest = get_next_file(file_name, os.path.join(documents_dir, 'backup', subdir_name))
shutil.move(source, dest)
我在 Windows
中使用此 Python
代码:
shutil.move(documents_dir + "\" + file_name, documents_dir + "\backup\"
+ subdir_name + "\" + file_name)
当此代码被多次调用时,它会覆盖目标文件。我想移动文件 如果目的地已经存在,重命名它
例如file_name
= foo.pdf
并且在 backup
文件夹中将是 foo.pdf
、foo(1).pdf
、foo(2).pdf
等或类似的,例如带破折号
foo-1.pdf
、foo-2.pdf
等
您可以边走边查看 os.path.exists()
。
import os
import shutil
file_name = 'test.csv'
documents_dir = r'C:\BR\Test'
subdir_name = 'test'
# using os.path.join() makes your code easier to port to another OS
source = os.path.join(documents_dir, file_name)
dest = os.path.join(documents_dir, 'backup', subdir_name, file_name)
num = 0
# loop until we find a file that doesn't exist
while os.path.exists(dest):
num += 1
# use rfind to find your file extension if there is one
period = file_name.rfind('.')
# this ensures that it will work with files without extensions
if period == -1:
period = len(file_name)
# create our new destination
# we could extract the number and increment it
# but this allows us to fill in the gaps if there are any
# it has the added benefit of avoiding errors
# in file names like this "test(sometext).pdf"
new_file = f'{file_name[:period]}({num}){file_name[period:]}'
dest = os.path.join(documents_dir, 'backup', subdir_name, new_file)
shutil.move(source, dest)
或者由于这可能在循环中使用,您可以将其放入函数中。
import os
import shutil
def get_next_file(file_name, dest_dir):
dest = os.path.join(dest_dir, file_name)
num = 0
while os.path.exists(dest):
num += 1
period = file_name.rfind('.')
if period == -1:
period = len(file_name)
new_file = f'{file_name[:period]}({num}){file_name[period:]}'
dest = os.path.join(dest_dir, new_file)
return dest
file_name = 'test.csv'
documents_dir = r'C:\BR\Test'
subdir_name = 'test'
source = os.path.join(documents_dir, file_name)
dest = get_next_file(file_name, os.path.join(documents_dir, 'backup', subdir_name))
shutil.move(source, dest)