为什么运算符不给出不同的结果而是使用 = 给出正确答案

Question

 static int count = 0;

  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    count = 0;
    int n = sc.nextInt();
    int arr[][] = new int[n][n];
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < n; j++) {
        arr[i][j] = sc.nextInt();
      }
    }
    for (int i = 0; i < n ; i++) {
      row(arr, n, i);
      column(arr, n, i);
    }
    System.out.println(count);
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < n; j++) {
        System.out.print(arr[i][j] + " ");
      }
    }
  }

  static void row(int arr[][], int n, int row) {
    int x, y, min, yHold = 0;

    for (x = 0; x < n; x++) {
      boolean yes = false;
      min = arr[row][x];

      for (y = row; y < n; y++) {
        if (arr[y][x] < min) {
          min = arr[y][x];
          yHold = y;
          yes = true;
        }
      }
      if (yes) {
        int temp = arr[row][x];
        arr[row][x] = min;
        arr[yHold][x] = temp;
        count++;
      }
    }

如果我将 yes=true 替换为 yes=!yes，输出会有所不同。请帮忙，似乎无法弄清楚。函数行所涉及的问题部分是：

If we are at ith row, then we have to work with each column at a time from 0 to n−1 of this row. For any jth column, swap A[i][j] with the minimum of all the elements which are present in a column with index j and rows from indices i to n−1.

Answer 1

问题是语句可以执行多次。在 yes = true 的情况下，结果总是 yes 变成 true。但是对于 yes = !yes，结果是 yes 将在 true 和 false 之间翻转。

Answer 2

当您说 yes = true 时，它总是正确的。但是当你说 yes = !yes 它会在 true 和 false 之间来回翻转。

boolean yes = true;
for (int i = i < 10; i++) {
 System.out.println(yes);   
 yes =! yes;
}

打印

true
false
true
false
true
false
true
false
true
false

为什么运算符不给出不同的结果而是使用 = 给出正确答案

Why is not operator giving different result but using = giving correct answer

java

operators