使用嵌套进行对象映射的最佳方法 Json
Best Way to do Object Mapping with Nested Json
目前我正在尝试使用 Feign 和 Spring 编写一个与 public API 交互的网站。
我无法决定如何处理深度嵌套 JSON.
的对象映射
例如:
[
{
"type": "console",
"category": "Console",
"result_count": 1,
"shown_count": 1,
"result": [
{
"name": "Nintendo Switch",
"id": "nintendo-switch",
"platform": {
"name": "Nintendo",
"category": "nintendo",
"type": "platform"
},
"image": {
"url": "https://encrypted-tbn1.gstatic.com/shopping?q=tbn:ANd9GcRqJYIheMDjTE9WAHjMSW4bjh7OplS7Bep9CdsBBLWMwGdXim7xOG4&usqp=CAc",
"height": 409,
"width": 631
},
"min_price": 205,
"variations": [
{
"items": [
{
"hex_code": "#696969",
"name": "Gray",
"id": "space-gray",
"type": "color"
},
{
"hex_code": "#C0C0C0",
"name": "Silver",
"id": "silver",
"type": "color"
}
],
"name": "Color",
"type": "color"
},
{
"items": [
{
"name": "Nintendo",
"id": "nintendo",
"type": "platform"
}
],
"name": "Platform",
"type": "platform"
}
]
}
]
}
]
截至目前,我有一个 Java 文件,JSON 中的每个对象都有一个 class,我考虑过让对象映射器将所有内容放入一个哈希图。有没有更优雅的方法来做到这一点?
public class SearchResults {
private List<SearchResult> products;
private int resultCount;
private String type;
}
class SearchResult {
private String name;
private String slug;
private Image image;
}
class Image {
private String URL;
private String height;
private String width;
}
基于 json 文件,我设计了 类 并提供了将 json 文件解析为 java
public class Console{
String type;
String category;
int result_count;
int show_count;
Result [] result;
}
public class Result{
String name;
String id;
Platform platform;
Image image;
int mini_price;
Variation [] variations;
}
public class Platform{
String name;
String category;
String type;
}
public class Image{
String url;
int height;
int width;
}
public class Variation{
String name;
String type;
Item [] items;
}
public class Item{
String hex_code;
String name;
String id;
String type;
}
要解析的代码:
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.enable(SerializationFeature.INDENT_OUTPUT);
Console[] consoles = objectMapper.readValue(ResourceUtils.getFile("path of json file"), Console[].class);
logger.info("Continents -> {}",(Object)continents);
for(Console console:consoles) {
//read the data accordingly
}
目前我正在尝试使用 Feign 和 Spring 编写一个与 public API 交互的网站。 我无法决定如何处理深度嵌套 JSON.
的对象映射例如:
[
{
"type": "console",
"category": "Console",
"result_count": 1,
"shown_count": 1,
"result": [
{
"name": "Nintendo Switch",
"id": "nintendo-switch",
"platform": {
"name": "Nintendo",
"category": "nintendo",
"type": "platform"
},
"image": {
"url": "https://encrypted-tbn1.gstatic.com/shopping?q=tbn:ANd9GcRqJYIheMDjTE9WAHjMSW4bjh7OplS7Bep9CdsBBLWMwGdXim7xOG4&usqp=CAc",
"height": 409,
"width": 631
},
"min_price": 205,
"variations": [
{
"items": [
{
"hex_code": "#696969",
"name": "Gray",
"id": "space-gray",
"type": "color"
},
{
"hex_code": "#C0C0C0",
"name": "Silver",
"id": "silver",
"type": "color"
}
],
"name": "Color",
"type": "color"
},
{
"items": [
{
"name": "Nintendo",
"id": "nintendo",
"type": "platform"
}
],
"name": "Platform",
"type": "platform"
}
]
}
]
}
]
截至目前,我有一个 Java 文件,JSON 中的每个对象都有一个 class,我考虑过让对象映射器将所有内容放入一个哈希图。有没有更优雅的方法来做到这一点?
public class SearchResults {
private List<SearchResult> products;
private int resultCount;
private String type;
}
class SearchResult {
private String name;
private String slug;
private Image image;
}
class Image {
private String URL;
private String height;
private String width;
}
基于 json 文件,我设计了 类 并提供了将 json 文件解析为 java
public class Console{
String type;
String category;
int result_count;
int show_count;
Result [] result;
}
public class Result{
String name;
String id;
Platform platform;
Image image;
int mini_price;
Variation [] variations;
}
public class Platform{
String name;
String category;
String type;
}
public class Image{
String url;
int height;
int width;
}
public class Variation{
String name;
String type;
Item [] items;
}
public class Item{
String hex_code;
String name;
String id;
String type;
}
要解析的代码:
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.enable(SerializationFeature.INDENT_OUTPUT);
Console[] consoles = objectMapper.readValue(ResourceUtils.getFile("path of json file"), Console[].class);
logger.info("Continents -> {}",(Object)continents);
for(Console console:consoles) {
//read the data accordingly
}