Checkmarx Postgres查询形成错误SQL注入错误,SQL二阶注入错误JavaSpringboot
Checkmarx Postgres Query forming error SQL Injection error , SQL Second order injection error Java Springboot
我有一些执行数据库操作的 API。每当我将我的代码上传到 checkmarx 时,我都会收到以下错误,并且它被标记为高漏洞错误任何人都可以帮助我吗?
错误
应用程序的 CreateDatabaseAndMapToDomain 方法在 daas-springboot-CheckMarxIntegration\src\main\java\com\it\daas\apis\service\PostgresConnectionServiceImpl.java 的第 717 行使用 executeQuery 执行 SQL 查询。应用程序通过在没有适当清理的情况下将不受信任的字符串嵌入到查询中来构造此 SQL 查询。连接后的字符串被提交到数据库,并在数据库中进行相应的解析和执行。
攻击者可能能够将任意数据写入数据库,然后由应用程序在 daas-springboot-CheckMarxIntegration\src\main\java\com\it\daas\apis\service\PostgresConnectionServiceImpl.java 的第 678 行的 getDomains 方法中使用 executeQuery 检索这些数据。这些数据然后流经代码,直到它不经过清理直接用于 SQL 查询,然后提交给数据库服务器执行
这是我的函数
@Override
public String getDomains() throws SQLException {
String domainquery = "SELECT id,domain FROM domain";
Connection con = null;
PreparedStatement st = null;
ResultSet result = null;
try
{
con = ConnectToPostgresapibuilderDatabase(apibuilderConnectionString, apibuilderUserName,apibuilderPassword);
con.setSchema(this.schema);
st = con.prepareStatement(domainquery);
result = st.executeQuery();
ArrayList<DatabaseDomainBean> list = new ArrayList<DatabaseDomainBean>();
while (result.next()) {
list.add(new DatabaseDomainBean(result.getString("domain"), result.getString("id")));
}
return new JSONObject().put("domainlist", list).toString();
}
catch(Exception e)
{
e.printStackTrace();
return null;
}
finally{
result.close();
st.close();
con.close();
}
}
@Override
public String CreateDatabaseAndMapToDomain(String database, String[] domainIds, String password)
throws SQLException {
if (!this.apibuilderPassword.equals(password)) {
return null;
}
else if(database==null || domainIds==null || password ==null)
{
return "Failure";
}
Connection con =null;
PreparedStatement st =null;
ResultSet ispresent =null;
PreparedStatement mapquerystmnt =null;
ResultSet resultMapping = null;
try
{
con = ConnectToPostgresapibuilderDatabase(apibuilderConnectionString, apibuilderUserName,apibuilderPassword);
con.setSchema(this.schema);
for (int i = 0; i < domainIds.length; i++) {
con.setSchema(this.schema);
String IfExists = MessageFormat.format(
"SELECT databasename,domainid FROM Databases WHERE databasename IN (?) AND domainid IN (?)",
Utilitymethods.ConvertToMessageFormatCompatibleForm(database),
Utilitymethods.ConvertToMessageFormatCompatibleForm(domainIds[i]));
st = con.prepareStatement(IfExists);
st.setString(1, database);
st.setInt(2, Integer.parseInt(domainIds[i]));
ispresent = st.executeQuery();
if (!ispresent.next()) {
// INSERT INTO Databases (databasename,domainid) VALUES ('Teradata','1')
String mapquery = MessageFormat.format(
"INSERT INTO Databases (databasename,domainid) VALUES (?,?) returning Id",
Utilitymethods.ConvertToMessageFormatCompatibleForm(database),
Utilitymethods.ConvertToMessageFormatCompatibleForm(domainIds[i]));
mapquerystmnt = con.prepareStatement(mapquery);
mapquerystmnt.setString(1, database);
mapquerystmnt.setInt(2, Integer.parseInt(domainIds[i]));
resultMapping = mapquerystmnt.executeQuery();
}
}
return "Success";
}
catch(Exception e)
{
e.printStackTrace();
return "Failure";
}
finally
{
ispresent.close();
st.close();
resultMapping.close();
mapquerystmnt.close();
con.close();
}
}
@Override
public String getDomains() throws SQLException {
String domainquery = "SELECT id,domain FROM domain";
Connection con = null;
PreparedStatement st = null;
ResultSet result = null;
try
{
con = ConnectToPostgresapibuilderDatabase(apibuilderConnectionString, apibuilderUserName,apibuilderPassword);
con.setSchema(this.schema);
st = con.prepareStatement(domainquery);
result = st.executeQuery();
ArrayList<DatabaseDomainBean> list = new ArrayList<DatabaseDomainBean>();
while (result.next()) {
list.add(new DatabaseDomainBean(result.getString("domain"), result.getString("id")));
}
return new JSONObject().put("domainlist", list).toString();
}
catch(Exception e)
{
e.printStackTrace();
return null;
}
finally{
result.close();
st.close();
con.close();
}
}
直接用 st = con.prepareStatement("SELECT id,domain FROM domain")
试试。由于 String domainquery = "SELECT id,domain FROM domain"
声明和 sql 注入的可能性,看起来 checkmarx 很困惑。
我有一些执行数据库操作的 API。每当我将我的代码上传到 checkmarx 时,我都会收到以下错误,并且它被标记为高漏洞错误任何人都可以帮助我吗?
错误
应用程序的 CreateDatabaseAndMapToDomain 方法在 daas-springboot-CheckMarxIntegration\src\main\java\com\it\daas\apis\service\PostgresConnectionServiceImpl.java 的第 717 行使用 executeQuery 执行 SQL 查询。应用程序通过在没有适当清理的情况下将不受信任的字符串嵌入到查询中来构造此 SQL 查询。连接后的字符串被提交到数据库,并在数据库中进行相应的解析和执行。
攻击者可能能够将任意数据写入数据库,然后由应用程序在 daas-springboot-CheckMarxIntegration\src\main\java\com\it\daas\apis\service\PostgresConnectionServiceImpl.java 的第 678 行的 getDomains 方法中使用 executeQuery 检索这些数据。这些数据然后流经代码,直到它不经过清理直接用于 SQL 查询,然后提交给数据库服务器执行
这是我的函数
@Override
public String getDomains() throws SQLException {
String domainquery = "SELECT id,domain FROM domain";
Connection con = null;
PreparedStatement st = null;
ResultSet result = null;
try
{
con = ConnectToPostgresapibuilderDatabase(apibuilderConnectionString, apibuilderUserName,apibuilderPassword);
con.setSchema(this.schema);
st = con.prepareStatement(domainquery);
result = st.executeQuery();
ArrayList<DatabaseDomainBean> list = new ArrayList<DatabaseDomainBean>();
while (result.next()) {
list.add(new DatabaseDomainBean(result.getString("domain"), result.getString("id")));
}
return new JSONObject().put("domainlist", list).toString();
}
catch(Exception e)
{
e.printStackTrace();
return null;
}
finally{
result.close();
st.close();
con.close();
}
}
@Override
public String CreateDatabaseAndMapToDomain(String database, String[] domainIds, String password)
throws SQLException {
if (!this.apibuilderPassword.equals(password)) {
return null;
}
else if(database==null || domainIds==null || password ==null)
{
return "Failure";
}
Connection con =null;
PreparedStatement st =null;
ResultSet ispresent =null;
PreparedStatement mapquerystmnt =null;
ResultSet resultMapping = null;
try
{
con = ConnectToPostgresapibuilderDatabase(apibuilderConnectionString, apibuilderUserName,apibuilderPassword);
con.setSchema(this.schema);
for (int i = 0; i < domainIds.length; i++) {
con.setSchema(this.schema);
String IfExists = MessageFormat.format(
"SELECT databasename,domainid FROM Databases WHERE databasename IN (?) AND domainid IN (?)",
Utilitymethods.ConvertToMessageFormatCompatibleForm(database),
Utilitymethods.ConvertToMessageFormatCompatibleForm(domainIds[i]));
st = con.prepareStatement(IfExists);
st.setString(1, database);
st.setInt(2, Integer.parseInt(domainIds[i]));
ispresent = st.executeQuery();
if (!ispresent.next()) {
// INSERT INTO Databases (databasename,domainid) VALUES ('Teradata','1')
String mapquery = MessageFormat.format(
"INSERT INTO Databases (databasename,domainid) VALUES (?,?) returning Id",
Utilitymethods.ConvertToMessageFormatCompatibleForm(database),
Utilitymethods.ConvertToMessageFormatCompatibleForm(domainIds[i]));
mapquerystmnt = con.prepareStatement(mapquery);
mapquerystmnt.setString(1, database);
mapquerystmnt.setInt(2, Integer.parseInt(domainIds[i]));
resultMapping = mapquerystmnt.executeQuery();
}
}
return "Success";
}
catch(Exception e)
{
e.printStackTrace();
return "Failure";
}
finally
{
ispresent.close();
st.close();
resultMapping.close();
mapquerystmnt.close();
con.close();
}
}
@Override
public String getDomains() throws SQLException {
String domainquery = "SELECT id,domain FROM domain";
Connection con = null;
PreparedStatement st = null;
ResultSet result = null;
try
{
con = ConnectToPostgresapibuilderDatabase(apibuilderConnectionString, apibuilderUserName,apibuilderPassword);
con.setSchema(this.schema);
st = con.prepareStatement(domainquery);
result = st.executeQuery();
ArrayList<DatabaseDomainBean> list = new ArrayList<DatabaseDomainBean>();
while (result.next()) {
list.add(new DatabaseDomainBean(result.getString("domain"), result.getString("id")));
}
return new JSONObject().put("domainlist", list).toString();
}
catch(Exception e)
{
e.printStackTrace();
return null;
}
finally{
result.close();
st.close();
con.close();
}
}
直接用 st = con.prepareStatement("SELECT id,domain FROM domain")
试试。由于 String domainquery = "SELECT id,domain FROM domain"
声明和 sql 注入的可能性,看起来 checkmarx 很困惑。