带计数器的骰子滚动程序

Question

我是编程新手，我有一个任务我自己无法解决。

任务是编写一个程序，让您决定掷多少个骰子，1 到 5 个，并检查您是否输入错误。每次掷骰后，都会显示骰子的数量和到目前为止的总数。如果骰子掷出 6，则它不包括在总数中，您将获得更多掷骰。这就是我被困的地方。我希望我的程序在骰子变成 6 时重新启动循环，并且只是将 ad 2 滚动到 sumDices 并继续循环，但我无法让它工作。

这是我的代码：

import random
numDices=0
total = 0
print("------------")
print("DICE ROLLING")
print("------------")
print()
exit=False
reset=False
while True:
    while True:
        numDices=int(input("How many dices to throw? (1-5) "))
        if numDices<1 or numDices>5:
            print("Wrong input, try again")
            break
        while True:
            if reset==True:
                break
            for i in range(numDices):
                dicesArray = list(range(numDices))
                dicesArray[i] = random.randint(1, 6)
                print(dicesArray[i])
                total += dicesArray[i]
                if dicesArray[i] == 1:
                    print("You rolled a one, the total is: ",str(total))
                elif dicesArray[i] == 2:
                    print("You rolled a two, the total is: ",str(total))
                elif dicesArray[i] == 3:
                    print("You rolled a three, the total is: ",str(total))
                elif dicesArray[i] == 4:
                    print("You rolled a four, the total is: ",str(total))
                elif dicesArray[i] == 5:
                    print("You rolled a five, the total is: ",str(total))
                elif dicesArray[i] == 6:
                    total-=6
                    numDices+=2
                    print("You rolled a six, rolling two new dices")
                    reset=True
        print("The total sum is",str(total),"with",numDices,"number of rolls.")
        print()
        restart=(input("Do you want to restart press Enter, to quit press 9. "))
        if restart=="9":
            exit=True
            break
        else:
            print()
            break
    if exit==True:
        break

Answer 1

您可以按照以下方式进行，稍微修改您的代码，计算可用的骰子。我也减少了那里的嵌套循环

import random
numDices=0
total = 0
print("------------")
print("DICE ROLLING")
print("------------")
print()
start = True
while start:
    numDices=int(input("How many dices to throw? (1-5) "))
    if numDices<1 or numDices>5:
        print("Wrong input, try again")
        break
    total = 0
    dices_counter = 0
    while numDices > 0 :
        eyes = random.randint(1, 6)
        dices_counter+=1 
        total += eyes
        if eyes == 1:
            print("You rolled a one, the total is: ",str(total))
            numDices-=1
        elif eyes == 2:
            print("You rolled a two, the total is: ",str(total))
            numDices-=1
        elif eyes == 3:
            print("You rolled a three, the total is: ",str(total))
            numDices-=1
        elif eyes == 4:
            print("You rolled a four, the total is: ",str(total))
            numDices-=1
        elif eyes == 5:
            print("You rolled a five, the total is: ",str(total))
            numDices-=1
        elif eyes == 6:
            total-=6
            numDices+=2
            print("You rolled a six, rolling two new dices")
    print("The total sum is",str(total),"with",dices_counter,"number of rolls.")
    print()
    start=(input("Do you want to restart press Enter, to quit press 9. "))
    if start=="9":
        break
    else:
        print()
        start = True

Answer 2

为了解决您的问题，我会将您当前的 for 循环替换为 while 循环

此外，我在你的代码中看到了很多不必要的东西，我会尽量列出它们:

为什么要用那么多"while True"？
为什么不直接使用 exit() 函数退出而不是使用 a 变量?
所有的 if 部分真的有必要吗，你不能只打印数？

这是我的建议：

import random
remaining_dices=0
total = 0
print("------------")
print("DICE ROLLING")
print("------------")
print()

while True:
    remaining_dices=int(input("How many dices to throw? (1-5) "))
    if remaining_dices<1 or remaining_dices>5:
        print("Wrong input, try again")
        break
    dicesArray = list()
    while remaining_dices>0:
        dice_value = random.randint(1, 6)
        dicesArray.append(dice_value)
        print(dice_value)
        total += dice_value
        remaining_dices -= 1
        if(dice_value == 6):
            total-=6
            remaining_dices +=2
            print("You rolled a 6, rolling two new dices")
        else:
            print("You rolled a " + str(dice_value) + ", the total is : " +str(total))

    restart=(input("Do you want to restart press Enter, to quit press 9. "))
    if restart=="9":
        exit()
    else:
        print()

Answer 3

for i in range(numDices):

只要 range(numDices) 为 evaluated/executed，您的 for 循环就会限制迭代次数。当您尝试使用 numDices+=2 增加迭代次数时，它没有任何效果，因为 range(numDices) 仅评估一次。

如果您希望能够更改迭代次数，请使用另一个 while 循环并使用 i 作为计数器。有点像。

i = 0
while i <= numDices:
    ...
    ...
    if ...:
        ...
    elif ...:
    ...
    i += 1

那么在suite for elif dicesArray[i] == 6:语句中numDices += 2会有效的增加迭代次数

我看到另一个你没有提到的问题。您从基于 numDices 原始值的固定长度列表开始，然后使用 i 作为该列表的索引。

dicesArray = list(range(numDices))`
...
dicesArray[i]
...

如果 i 可能大于 original numDices（大于 len(dicesArray)），您最终会得到一个 IndexError。您可能应该从一个空列表开始并附加到它。要获得最近的掷骰结果，请使用 dicesArray[-1] 而不是 dicesArray[i].

...
dicesArray = []
i = 0
while i <= numDices:
    dicesArray.append(random.randint(1, 6))
    total += dicesArray[-1]
    if dicesArray[-1] == 1:
        ...
    ...

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Answer 4

使用递归函数

import random

total = 0
diceRollList = []

# Define dice rolling function
def rollDice():
    rollResult = random.randint(1, 6)
    if rollResult == 6:
        # If 6 Rolled run two more rolls and sum the results
        print("Rolled a 6 Rolling 2 more")
        return sum([rollDice() for _ in range(2)])
    # If 6 not rolled return the result
    print(f"Rolled a {rollResult}")
    return rollResult

while True:

    numberOfDice = int(input("How many Die to throw: "))

    if numberOfDice not in range(1, 6):
        print("Number of dice should be between 1 and 5")
        break

    for dice in range(numberOfDice):
        print(f"Rolling Dice {dice}")
        # Add result to the total
        total += rollDice()
        print(f"Running Total: {total}")

Answer 5

这个跟踪它滚动了多少：

import random

a = int(0)
b = int(0)
c = int(0)
d = int(0)
e = int(0)
f = int(0)
limit = 101
count = 0

while True:
    g = (random.randint(1, 6))
    print(g)
    count += 1
    if g == 1:
        a += 1
    elif g == 2:
        b += 1
    elif g == 3:
        c += 1
    elif g == 4:
        d += 1
    elif g == 5:
        e += 1
    elif g == 6:
        f += 1
    if count > limit:
        break

print(f"There are {a} 1's")
print(f"There are {b} 2's")
print(f"There are {c} 3's")
print(f"There are {d} 4's")
print(f"There are {e} 5's")
print(f"There are {f} 6's")

带计数器的骰子滚动程序

Dice rolling program with counter

python

python-3.x

list

random

dice