比较 rpy2 中的方法

Question

我有一个 rpy2 脚本：

from rpy2.robjects.packages import importr
binom = importr('binom')
from rpy2 import robjects

robjects.r('''library(binom)
p = seq(0,1,.01)
coverage = binom.coverage(p, 10, method="bayes", type = "central")$coverage
''')

我想用它来比较方法列表的结果：

methods = [("bayes", type = "central"),("asymptotic")]

for method in methods:
    robjects.globalenv["method"] = robjects.r(method)
    robjects.r('''library(binom)
    p = seq(0,1,0.01)
    coverage = binom.coverage(p, 10, method=method)$coverage
    ''')

第一行给我：

invalid syntax

我想为贝叶斯方法包含 'type'，但是当我删除它以获取列表中的语法时，我仍然收到错误消息：

object 'bayes' not found

Answer 1

robjects.r() 收到一个字符串，因此对于此特定任务，您只需将单词 method 替换为正确的字符串即可。使用两个引号（单引号和双引号）就可以了，因为 .replace() 将放弃外部引号并替换文本，保留单引号。

from rpy2.robjects.packages import importr
binom = importr('binom')
from rpy2 import robjects

methods = ["'bayes', type='central'","'asymptotic'"]
for method in methods:
    r_string = """library(binom)
    p = seq(0,1,0.01)
    coverage = binom.coverage(p, 10, method=TECHNIQUE)$coverage
    """.replace('TECHNIQUE',method)
    robjects.r(r_string)

比较 rpy2 中的方法

Compare Methods in rpy2

python

list

for-loop

rpy2