通过 Rcpp 和 bit64 R 包将最大 int64_t 变量值从 C++ 传递到 R
Passing largest int64_t variable values from C++ to R via Rcpp and the bit64 R package
我写了一个函数来计算 2 的给定次方。我想使用 64 位整数。在 R 中,bit64 包具有以下最大和最小限制:
来自R
:
> bit64::lim.integer64()
integer64
[1] -9223372036854775807 9223372036854775807
这是 -(2^63)
和 2^63
。
但是,出于某种原因,我的 Rcpp
代码只能将 2^62
传回 R。这是我的函数的代码,它将 2 提高到给定的幂(注意:我使用 bit -转变以实现这一目标):
C++
代码:
// [[Rcpp::export]]
Rcpp::NumericVector i2_to_the_power_j ( int64_t j )
{
int64_t base = 1;
int64_t value = base << j;
// cout << "C++ value: " << value << "\n";
// Create a vector of length 1 with `value` as the sole contents
const std::vector<int64_t> v(1, value);
const size_t len = v.size();
Rcpp::NumericVector nn(len); // storage vehicle we return them in
// transfers values 'keeping bits' but changing type
// using reinterpret_cast would get us a warning
std::memcpy(&(nn[0]), &(v[0]), len * sizeof(double));
nn.attr("class") = "integer64";
return nn;
return value;
}
但是,当我运行这个在R
时,我无法获得最大的possible/limiting值!
来自R
:
>library(Rcpp)
>library(bit64)
> sourceCpp("./hilbert_curve_copy.cpp")
> # I can get 2^62
> i2_to_the_power_j(62)
integer64
[1] 4611686018427387904
> # ...but I cannot get 2^63
> i2_to_the_power_j(63)
integer64
[1] <NA>
> # I cannot get 2^63, despite bit64 package claiming it can
> # handle integers of this size
> bit64::lim.integer64()
integer64
[1] -9223372036854775807 9223372036854775807
我是不是漏掉了什么?请指教,感谢您的宝贵时间。
我的快速猜测(事实证明是正确的):最大值 本身 可能被标记为 NA。所以计算 'one minus' 这个值并尝试一下。
我的快速猜测:最大值可能是标记为 NA 的值。所以计算 'one minus' 该值并尝试
// [[Rcpp::export]]
Rcpp::NumericVector largeval ( ) {
int64_t val = 9223372036854775807LL - 1;
Rcpp::Rcout << "C++ value: " << val << "\n";
Rcpp::NumericVector dbl(1);
std::memcpy(&(dbl[0]), &val, sizeof(double));
dbl.attr("class") = "integer64";
return dbl;
}
我将其添加到您的代码中,运行 它产生:
R> largeval()
C++ value: 9223372036854775806
integer64
[1] 9223372036854775806
R>
以下完整代码以防万一。
代码
#include <Rcpp.h>
// [[Rcpp::export]]
Rcpp::NumericVector i2_to_the_power_j ( int64_t j )
{
int64_t base = 1;
int64_t value = base << j;
// cout << "C++ value: " << value << "\n";
// Create a vector of length 1 with `value` as the sole contents
const std::vector<int64_t> v(1, value);
const size_t len = v.size();
Rcpp::NumericVector nn(len); // storage vehicle we return them in
// transfers values 'keeping bits' but changing type
// using reinterpret_cast would get us a warning
std::memcpy(&(nn[0]), &(v[0]), len * sizeof(double));
nn.attr("class") = "integer64";
return nn;
return value;
}
// [[Rcpp::export]]
Rcpp::NumericVector largeval ( ) {
int64_t val = 9223372036854775807LL - 1;
Rcpp::Rcout << "C++ value: " << val << "\n";
Rcpp::NumericVector dbl(1);
std::memcpy(&(dbl[0]), &val, sizeof(double));
dbl.attr("class") = "integer64";
return dbl;
}
/*** R
library(bit64)
# I can get 2^62
i2_to_the_power_j(62)
# ...but I cannot get 2^63
i2_to_the_power_j(63)
# I cannot get 2^63, despite bit64 package claiming it can
# handle integers of this size
bit64::lim.integer64()
largeval()
*/
我写了一个函数来计算 2 的给定次方。我想使用 64 位整数。在 R 中,bit64 包具有以下最大和最小限制:
来自R
:
> bit64::lim.integer64()
integer64
[1] -9223372036854775807 9223372036854775807
这是 -(2^63)
和 2^63
。
但是,出于某种原因,我的 Rcpp
代码只能将 2^62
传回 R。这是我的函数的代码,它将 2 提高到给定的幂(注意:我使用 bit -转变以实现这一目标):
C++
代码:
// [[Rcpp::export]]
Rcpp::NumericVector i2_to_the_power_j ( int64_t j )
{
int64_t base = 1;
int64_t value = base << j;
// cout << "C++ value: " << value << "\n";
// Create a vector of length 1 with `value` as the sole contents
const std::vector<int64_t> v(1, value);
const size_t len = v.size();
Rcpp::NumericVector nn(len); // storage vehicle we return them in
// transfers values 'keeping bits' but changing type
// using reinterpret_cast would get us a warning
std::memcpy(&(nn[0]), &(v[0]), len * sizeof(double));
nn.attr("class") = "integer64";
return nn;
return value;
}
但是,当我运行这个在R
时,我无法获得最大的possible/limiting值!
来自R
:
>library(Rcpp)
>library(bit64)
> sourceCpp("./hilbert_curve_copy.cpp")
> # I can get 2^62
> i2_to_the_power_j(62)
integer64
[1] 4611686018427387904
> # ...but I cannot get 2^63
> i2_to_the_power_j(63)
integer64
[1] <NA>
> # I cannot get 2^63, despite bit64 package claiming it can
> # handle integers of this size
> bit64::lim.integer64()
integer64
[1] -9223372036854775807 9223372036854775807
我是不是漏掉了什么?请指教,感谢您的宝贵时间。
我的快速猜测(事实证明是正确的):最大值 本身 可能被标记为 NA。所以计算 'one minus' 这个值并尝试一下。
我的快速猜测:最大值可能是标记为 NA 的值。所以计算 'one minus' 该值并尝试
// [[Rcpp::export]]
Rcpp::NumericVector largeval ( ) {
int64_t val = 9223372036854775807LL - 1;
Rcpp::Rcout << "C++ value: " << val << "\n";
Rcpp::NumericVector dbl(1);
std::memcpy(&(dbl[0]), &val, sizeof(double));
dbl.attr("class") = "integer64";
return dbl;
}
我将其添加到您的代码中,运行 它产生:
R> largeval()
C++ value: 9223372036854775806
integer64
[1] 9223372036854775806
R>
以下完整代码以防万一。
代码
#include <Rcpp.h>
// [[Rcpp::export]]
Rcpp::NumericVector i2_to_the_power_j ( int64_t j )
{
int64_t base = 1;
int64_t value = base << j;
// cout << "C++ value: " << value << "\n";
// Create a vector of length 1 with `value` as the sole contents
const std::vector<int64_t> v(1, value);
const size_t len = v.size();
Rcpp::NumericVector nn(len); // storage vehicle we return them in
// transfers values 'keeping bits' but changing type
// using reinterpret_cast would get us a warning
std::memcpy(&(nn[0]), &(v[0]), len * sizeof(double));
nn.attr("class") = "integer64";
return nn;
return value;
}
// [[Rcpp::export]]
Rcpp::NumericVector largeval ( ) {
int64_t val = 9223372036854775807LL - 1;
Rcpp::Rcout << "C++ value: " << val << "\n";
Rcpp::NumericVector dbl(1);
std::memcpy(&(dbl[0]), &val, sizeof(double));
dbl.attr("class") = "integer64";
return dbl;
}
/*** R
library(bit64)
# I can get 2^62
i2_to_the_power_j(62)
# ...but I cannot get 2^63
i2_to_the_power_j(63)
# I cannot get 2^63, despite bit64 package claiming it can
# handle integers of this size
bit64::lim.integer64()
largeval()
*/