如何使用underscore.js过滤列表元素中带有匹配参数的对象？

Question

nodedatasource = [
    {"id":1,'name':'a'},
    {"id":2,'name':'b'},
    {"id":3,'name':'c'},
    {"id":4,'name':'d'},
]
list_ids = [3,2] #

我想获得一个过滤后的数据源对象列表，其 id 在 list_ids?
我尝试过这种方法。

..需要更正

datanode =_.filter(nodedatasource, function(element,ids){
    return element.id in ids
})

Answer 1

const list_ids = [3, 2]
const datanode =_.filter(nodedatasource,function(element){
                return list_ids.includes( element.id )
        })
//datanode = [{"id":2,'name':'b'},
//            {"id":3,'name':'c'}]

Answer 2

如果你只想纯粹地做这件事 JavaScript

var datasource = [{"id":1,'name':'a'},
              {"id":2,'name':'b'},
              {"id":3,'name':'c'},
              {"id":4,'name':'d'},
            ]
var list_ids = [3,2]

var filteredArray = datasource.filter(elem => list_ids.includes(elem.id));

console.log(filteredArray)

Answer 3

另一种完全在 underscorejs 中完成的方法:

list_ids = [3, 2]
datanode = _.filter(nodedatasource,function(element,list_ids){ 
              return _.contains(list_ids,element.id) 
             });
//datanode = [{"id":2,'name':'b'},
//            {"id":3,'name':'c'}]

如何使用underscore.js过滤列表元素中带有匹配参数的对象？

how to filter those objects with match parameter in list element using underscore.js?

javascript

underscore.js