在房间数据库中处理这种关系的最佳方式

Question

我有三个 table，我在这里有一个多对多的关系：

联系人table：

@Entity(tableName = "T_Contacts")
class Contact(
@PrimaryKey(autoGenerate = true) @ColumnInfo(name = "_id") var id: Long,
@ColumnInfo(name = "phoneNumber")
var phoneNumber: String = "",

@ColumnInfo(name = "name")
var name: String = "",

@ColumnInfo(name = "active")
var active: Int = 1

@ColumnInfo(name = "contactId")
var contactId: Long = -1

@ColumnInfo(name = "phoneContactId")
var phoneContactId: String = ""

}

电子邮件 table：

@Entity(tableName = "T_EmailAddress")
class EmailAddress(
@PrimaryKey(autoGenerate = true) @ColumnInfo(name = "_id")
var id : Long,
@ColumnInfo(name="emailAddress")
var emailAddress: String,
@ColumnInfo(name="active")
var active : Int) {

}

和联想table：

@Entity(tableName = "T_EmailAddressContact",
foreignKeys = [ForeignKey(
    entity = Contact::class,
    parentColumns = arrayOf("contactId"),
    childColumns = arrayOf("contactId"),
    onDelete=ForeignKey.CASCADE),
    ForeignKey(
        entity = EmailAddress::class,
        parentColumns = arrayOf("emailId"),
        childColumns = arrayOf("emailId"),
        onDelete=ForeignKey.CASCADE)]
  )
class EmailAddressContactCrossRef(
@PrimaryKey(autoGenerate = true)
@ColumnInfo(name = "_id")
var id: Long,
@ColumnInfo(name="contactId")
var contactId: Long,
@ColumnInfo(name="emailId")
var emailId : Long,
@ColumnInfo(name="active")
var active : Int ) {

如何使用关系获取所有电子邮件联系人的列表？我试过了：

data class EmailAddressContact(
@Embedded val contact: EmailAddress,
@Relation(parentColumn = "contactId",
    entityColumn = "contactId",
    associateBy = Junction(EmailAddressContactCrossRef::class)
)

val listContacts: List<Contact>
)

但这只会让我得到一个特定电子邮件地址的所有联系人列表。我想要这样的东西：

data class EmailAddressContact { 
    val id: Long,
    val emailAddress: EmailAddress,
    val contact: Contact,
    val active: Boolean

}

通过调用查询：

@Transaction
@Query("SELECT * FROM T_EmailAddressContact")
fun getAllEmailAddressAndContacts(): List<EmailAddressContact>

Answer 1

根据您的 EmailAddressContact 结构，您似乎不需要使用联结，只需使用关系。试试这个方法：

data class EmailAddressContact(
    @Embedded val emailAddressContactCrossRef: EmailAddressContactCrossRef, // <- there you'll get "id" and "active" fields
    @Relation(
         parentColumn = "contactId",
         entityColumn = "contactId"
    )
    val contact: Contact,
    @Relation(
         parentColumn = "emailId",
         entityColumn = "_id"
    )
    val emailAddress: EmailAddress
)

你在问题中提到的查询应该适合

在房间数据库中处理这种关系的最佳方式

Best way to handle this relation in Room Database

android

database-relations

android-room