关于xv6(riscv)调试的问题-来自MIT 6.S081/6.828 2019 OS课程

Question

我正在尝试调试用户程序，但是当我这样做时：

open a terminal:make qemu-gdb
another terminal:
riscv64-unknown-elf-gdb 
file wc(or any other user programs)
it says:
(gdb) file wc
warning: A handler for the OS ABI "GNU/Linux" is not built into this configuration
of GDB. Attempting to continue with the default riscv settings.

warning: A handler for the OS ABI "GNU/Linux" is not built into this configuration
of GDB. Attempting to continue with the default riscv settings.

Reading symbols from wc...
(No debugging symbols found in wc)

我编辑了 Makefile，并在 CFLAGS 和 LDFLAGS 中都添加了 -g，但是它不起作用我想知道如何调试用户程序

如果你能回复并帮助我，我将不胜感激

ps:这里是MakeFile和项目树

树：https://paste.ubuntu.com/p/s9JGY8d4Z9/ 生成文件：https://paste.ubuntu.com/p/Zp6HXcF4Vq/

Answer 1

我终于想通了：

文件命令后应跟可执行文件的路径

所以作为树 suggests:if 我想调试 wc，我应该输入：

file user/_wc

然后设置断点，然后继续

然后运行在 qemu 中 wc

关于xv6(riscv)调试的问题-来自MIT 6.S081/6.828 2019 OS课程

Questions about debugging in xv6(riscv) -from MIT 6.S081/6.828 2019 OS course

linux

gdb

xv6

riscv