如何用javascript中的图像src更改标识符的url?
How to change url of identifier with src of image in javascript?
我想将光标悬停在图像上并将其作为另一个 div 的背景图像显示。我在 js 中执行以下操作:
function upDate(previewPic){
document.getElementById("image").style.backgroundImage="url(previewPic.src)";
}
src 包含在线 link 所以不用担心。我想通过 id "image" 访问 div 并将其 bg 图片的 url 替换为我悬停的图片的 src。我进行了一个函数调用,将当前图像的对象发送给我。
完整代码如下:
function upDate(previewPic){
document.getElementById("image").style.backgroundImage="url(previewPic.src)";
}
#image {
line-height: 650px;
width: 575px;
height: 650px;
border: 5px solid black;
margin: 0 auto;
background-color: #8e68ff;
background-image: url('');
background-repeat: no-repeat;
color: #FFFFFF;
text-align: center;
background-size: 100%;
margin-bottom: 25px;
font-size: 150%;
}
.preview {
width: 10%;
margin-left: 17%;
border: 10px solid black;
}
<div id="image">
Hover over an image below to display here.
</div>
<img class="preview" alt="Styling with a Bandana" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg" onmouseover="upDate(this)" onmouseout="unDo()">
<img class="preview" alt="With My Boy" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon2.JPG" onmouseover="upDate(this)" onmouseout="unDo()">
<img class="preview" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon3.jpg" alt="Young Puppy" onmouseover="upDate(this)" onmouseout="unDo()">
您想应用如下内容CSS:
background-image: url("https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg");
但你实际上是这样做的:
background-image: url(previewPic.src);
这是您需要更新的 javascript 行,已更正字符串连接:
document.getElementById("image").style.backgroundImage= "url('" + previewPic.src + "')";
代码片段:
function upDate(previewPic){
document.getElementById("image").style.backgroundImage= "url('" + previewPic.src + "')";
}
#image {
line-height: 650px;
width: 575px;
height: 650px;
border: 5px solid black;
margin: 0 auto;
background-color: #8e68ff;
background-image: url('');
background-repeat: no-repeat;
color: #FFFFFF;
text-align: center;
background-size: 100%;
margin-bottom: 25px;
font-size: 150%;
}
.preview {
width: 10%;
margin-left: 17%;
border: 10px solid black;
}
<div id="image">
Hover over an image below to display here.
</div>
<img class="preview" alt="Styling with a Bandana" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg" onmouseover="upDate('https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg')" onmouseout="unDo()">
<img class="preview" alt="With My Boy" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon2.JPG" onmouseover="upDate('https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon2.JPG')" onmouseout="unDo()">
<img class="preview" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon3.jpg" alt="Young Puppy" onmouseover="upDate('https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon3.jpg')" onmouseout="unDo()">
我想将光标悬停在图像上并将其作为另一个 div 的背景图像显示。我在 js 中执行以下操作:
function upDate(previewPic){
document.getElementById("image").style.backgroundImage="url(previewPic.src)";
}
src 包含在线 link 所以不用担心。我想通过 id "image" 访问 div 并将其 bg 图片的 url 替换为我悬停的图片的 src。我进行了一个函数调用,将当前图像的对象发送给我。
完整代码如下:
function upDate(previewPic){
document.getElementById("image").style.backgroundImage="url(previewPic.src)";
}
#image {
line-height: 650px;
width: 575px;
height: 650px;
border: 5px solid black;
margin: 0 auto;
background-color: #8e68ff;
background-image: url('');
background-repeat: no-repeat;
color: #FFFFFF;
text-align: center;
background-size: 100%;
margin-bottom: 25px;
font-size: 150%;
}
.preview {
width: 10%;
margin-left: 17%;
border: 10px solid black;
}
<div id="image">
Hover over an image below to display here.
</div>
<img class="preview" alt="Styling with a Bandana" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg" onmouseover="upDate(this)" onmouseout="unDo()">
<img class="preview" alt="With My Boy" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon2.JPG" onmouseover="upDate(this)" onmouseout="unDo()">
<img class="preview" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon3.jpg" alt="Young Puppy" onmouseover="upDate(this)" onmouseout="unDo()">
您想应用如下内容CSS:
background-image: url("https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg");
但你实际上是这样做的:
background-image: url(previewPic.src);
这是您需要更新的 javascript 行,已更正字符串连接:
document.getElementById("image").style.backgroundImage= "url('" + previewPic.src + "')";
代码片段:
function upDate(previewPic){
document.getElementById("image").style.backgroundImage= "url('" + previewPic.src + "')";
}
#image {
line-height: 650px;
width: 575px;
height: 650px;
border: 5px solid black;
margin: 0 auto;
background-color: #8e68ff;
background-image: url('');
background-repeat: no-repeat;
color: #FFFFFF;
text-align: center;
background-size: 100%;
margin-bottom: 25px;
font-size: 150%;
}
.preview {
width: 10%;
margin-left: 17%;
border: 10px solid black;
}
<div id="image">
Hover over an image below to display here.
</div>
<img class="preview" alt="Styling with a Bandana" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg" onmouseover="upDate('https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon.jpg')" onmouseout="unDo()">
<img class="preview" alt="With My Boy" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon2.JPG" onmouseover="upDate('https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon2.JPG')" onmouseout="unDo()">
<img class="preview" src="https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon3.jpg" alt="Young Puppy" onmouseover="upDate('https://s3-us-west-2.amazonaws.com/s.cdpn.io/389177/bacon3.jpg')" onmouseout="unDo()">