WPF 数据网格行 header 切换按钮视觉状态从代码隐藏更改

WPF datagrid row header toggle button visualstate change from code behind

在 WPF 中,我在数据网格行 header 中使用切换按钮来显示每个 parent 数据网格行作为 child 数据网格的详细可见性。当我单击切换按钮时,相应 parent 数据网格行的视觉状态将更改为 "Checked" 状态。它工作正常。但与此同时,我想将所有其他 parent 数据网格行的视觉状态设为 "Unchecked" 或 "Normal",而无需单击每个切换按钮。我正在使用以下代码。但它不能正常工作。但是如果我点击每个切换按钮,那么它的视觉状态就会正确改变。

private void ToggleButton_Click(object sender, RoutedEventArgs e)
    {            
            DependencyObject obj = (DependencyObject)e.OriginalSource;
            while (!(obj is DataGridRow) && (obj != null))
            {
                obj = VisualTreeHelper.GetParent(obj);
            }
            if (obj is DataGridRow)
            {
          if ((obj as DataGridRow).DetailsVisibility == Visibility.Visible)
                {
                    (obj as DataGridRow).IsSelected = false;
                    (obj as DataGridRow).DetailsVisibility = System.Windows.Visibility.Collapsed;
                }
                else if ((obj as DataGridRow).DetailsVisibility == Visibility.Collapsed)
                {
                    for (int i = 0; i < Data_Grid.Items.Count; i++)
                    {
                        DataGridRow itm = GetDataGridRowitem(i);

                            itm.IsSelected = false;
               itm.DetailsVisibility = System.Windows.Visibility.Collapsed;            

               VisualStateManager.GoToElementState(itm, "Unchecked", true);
                    }
                    DataTemplate dt = FindResource("tocchild") as DataTemplate;
                    Data_Grid.RowDetailsTemplate = dt;
                    (obj as DataGridRow).IsSelected = true;
                    (obj as DataGridRow).DetailsVisibility = Visibility.Visible;                        
                    VisualStateManager.GoToElementState((obj as DataGridRow), "Checked", true);
                }
            }}

我也试过了,

 VisualStateManager.GoToState((obj as DataGridRow), "Checked", true);

请帮帮我。 谢谢

datagrid 的第一列设置为此

 <DataGridTemplateColumn CellTemplate="{StaticResource ExpandDetails}" Width="30" />

并将此dataTemplate放入资源

<DataTemplate x:Key="ExpandDetails">
            <ToggleButton Name="ShowDetails" Height="20"
                              IsChecked="{Binding RelativeSource={RelativeSource AncestorType=DataGridRow}, 
                                                  Path=DetailsVisibility, 
                                                  Converter={StaticResource VisbilityToBooleanConverter}, 
                                                  Mode=TwoWay}" 
                              Margin="4" HorizontalAlignment="Right" FlowDirection="LeftToRight" BorderThickness="0" />
</DataGridTemplateColumn>

然后像这样创建VisbilityToBooleanConverter

public class VisbilityToBooleanConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        return (Visibility)value == Visibility.Visible;
    }

    public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        return (bool)value ? Visibility.Visible : Visibility.Collapsed;
    }
}

试试这个,

class VisibilityConverter : IValueConverter

Change Visual State

我通过将值 Toggle Button IsChecked 设置为 True 和 false 来解决它。

FrameworkElement tb = GetTemplateChildByName(row, "RowHeaderToggleButton");
                    (tb as ToggleButton).IsChecked = false;

GetTemplateChildByName 在哪里,

public static FrameworkElement GetTemplateChildByName(DependencyObject parent, string name)
{
    int childnum = VisualTreeHelper.GetChildrenCount(parent);
    for (int i = 0; i < childnum; i++)
    {
        var child = VisualTreeHelper.GetChild(parent, i);
        if (child is FrameworkElement &&

        ((FrameworkElement)child).Name == name)
        {
            return child as FrameworkElement;
        }
        else
        {
            var s = GetTemplateChildByName(child, name);
            if (s != null)
                return s;
        }
    }
    return null;
}

感谢大家。