Spotipy: AttributeError: 'list' object has no attribute 'split'

Question

我对 python 有点陌生 - 只有几个月 - 但我正在努力解决我在使用 Spotipy 获取某些音频功能时不断遇到的 AttributeError。

当我运行这个：

bb_songs = ['24ySl2hOPGCDcxBxFIqWBu', '5v4GgrXPMghOnBBLmveLac', etc...  # a list of Spotify song IDs
spotify = spotipy.Spotify(client_credentials_manager=SpotifyClientCredentials())
credentials = spotipy.oauth2.SpotifyClientCredentials()
print(spotify.audio_features(tracks=[bb_songs]))

我明白了：

(base) Matthews-MBP-2:spotipy MattJust$ python3 erase.py
Traceback (most recent call last):
  File "erase.py", line 20, in <module>
    print(spotify.audio_features(tracks=[bb_songs]))
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/spotipy/client.py", line 1243, in audio_features
    tlist = [self._get_id("track", t) for t in tracks]
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/spotipy/client.py", line 1243, in <listcomp>
    tlist = [self._get_id("track", t) for t in tracks]
  File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/site-packages/spotipy/client.py", line 1462, in _get_id
    fields = id.split(":")
AttributeError: 'list' object has no attribute 'split'

我是否认为 SpotiPy 中的 audio_features 函数有一个不喜欢我的列表的拆分函数，因为没有像 "'track' : ' 这样的字符串列表5v4GgrXPMghOnBBLmveLac'"?

如有任何帮助，我们将不胜感激！

马修

Answer 1

试试看 print(spotify.audio_features(tracks=bb_songs)) 去掉方括号

而不是 print(spotify.audio_features(tracks=[bb_songs]))

将您的列表用一组方括号括起来会创建一个列表，其中包含一个元素，即您的列表。该函数尝试遍历列表元素，对每个元素执行拆分函数。但是，由于您传递的是列表列表，因此函数 returns 出错。