无法使用 xml.etree.ElementTree 解析 html
Can't parse html using xml.etree.ElementTree
我正在尝试解析 google.com 的 xml,但是我收到 'not well-formed' 错误。为什么是这样?谢谢
➜ testing cat code.py
from urllib.request import urlopen; from xml.etree.ElementTree import fromstring
fromstring(urlopen('https://www.google.com').read().replace(b'<!doctype html>',b'<!DOCTYPE html>'))
➜ testing python3 code.py
Traceback (most recent call last):
File "code.py", line 2, in <module>
fromstring(urlopen('https://www.google.com').read().replace(b'<!doctype html>',b'<!DOCTYPE html>'))
File "/usr/local/Cellar/python/3.7.7/Frameworks/Python.framework/Versions/3.7/lib/python3.7/xml/etree/ElementTree.py", line 1315, in XML
parser.feed(text)
xml.etree.ElementTree.ParseError: not well-formed (invalid token): line 1, column 1826
➜ testing
您收到错误消息的原因可能是您正在尝试使用 XML 解析器解析 HTML;它不会工作。尝试使用带有 HTML 解析器的库。另外,我建议改为获取包含请求的页面。所以一起:
import requests
import lxml.html as lh
req = requests.get('https://www.google.com')
lh.fromstring(req.text)
它应该可以工作。
我正在尝试解析 google.com 的 xml,但是我收到 'not well-formed' 错误。为什么是这样?谢谢
➜ testing cat code.py
from urllib.request import urlopen; from xml.etree.ElementTree import fromstring
fromstring(urlopen('https://www.google.com').read().replace(b'<!doctype html>',b'<!DOCTYPE html>'))
➜ testing python3 code.py
Traceback (most recent call last):
File "code.py", line 2, in <module>
fromstring(urlopen('https://www.google.com').read().replace(b'<!doctype html>',b'<!DOCTYPE html>'))
File "/usr/local/Cellar/python/3.7.7/Frameworks/Python.framework/Versions/3.7/lib/python3.7/xml/etree/ElementTree.py", line 1315, in XML
parser.feed(text)
xml.etree.ElementTree.ParseError: not well-formed (invalid token): line 1, column 1826
➜ testing
您收到错误消息的原因可能是您正在尝试使用 XML 解析器解析 HTML;它不会工作。尝试使用带有 HTML 解析器的库。另外,我建议改为获取包含请求的页面。所以一起:
import requests
import lxml.html as lh
req = requests.get('https://www.google.com')
lh.fromstring(req.text)
它应该可以工作。