如何使用 WSGI 实现 Flask 应用按路径调度？

Question

我想使用一个域作为多个 flask 应用程序的暂存环境，这些应用程序最终将运行在它们自己的域上。

类似于：

example_staging.com/app1
example_staging.com/app2
example_staging.com/app3

其中：

example_staging.com/app1 与 app1.example_staging.com
example_staging.com/app2 与 app2.example_staging.com
example_staging.com/app3 与 app3.example_staging.com

或：

example_staging.com/app1 与 app1.com
example_staging.com/app2 与 app2.com
example_staging.com/app3 与 app3.com

入门应用：

from flask import Flask

app = Flask(__name__)

@app.route('/')
def hello_world():
    return 'Hello from Flask!'

WSGI 初学者配置文件：

import sys

project_home = u'/home/path/sample1'

if project_home not in sys.path:
    sys.path = [project_home] + sys.path

from app import app as application

参考：

http://flask.pocoo.org/docs/0.10/patterns/appdispatch/

我不知道在哪里添加文档中给出的示例代码以及 create_app、default_app、get_user_for_prefix 应该是什么样子。

注意：使用 PythonAnywhere

解决方案

Glenns 输入后的 WSGI 配置文件：

import sys

# add your project directory to the sys.path
project_home = u'/home/path/app1'
if project_home not in sys.path:
    sys.path = [project_home] + sys.path

from werkzeug.wsgi import DispatcherMiddleware
from app import app as app1
from app2.app import app as app2
from app3.app import app as app3

application = DispatcherMiddleware(app1, {
    '/app2':    app2,
    '/app3':    app3
})

文件夹结构：

app1 folder
    app2 folder
    app3 folder

Answer 1

这里要注意的关键是，您实际上将拥有 4 个应用程序（3 个单独的应用程序和一个组合的应用程序）。这忽略了 staging/live 区别，因为暂存和实时只是不同目录中彼此的副本。

创建每个单独的应用程序并让它们在各自的域上做出响应。然后创建一个新的应用程序，从各个应用程序导入 application 变量，并使用 DispatcherMiddleware 组合它们，就像您 link 文档页面上标题 "Combining Applications" 下的示例一样.

Answer 2

这对我有用：

文件夹结构

DISPATCHER (folder)
   dispatcher.py

   app1 (folder)
       __init__.py

   app2 (folder)
       __init__.py

   app3 (folder)
       __init__.py

dispatcher.py

from flask import Flask
from werkzeug.wsgi import DispatcherMiddleware #use the commented version below for Werkzeug >= v.1.0
#from werkzeug.middleware.dispatcher import DispatcherMiddleware
from werkzeug.exceptions import NotFound

from app1 import app as app1
from app2 import app as app2
from app3 import app as app3

app = Flask(__name__)

app.wsgi_app = DispatcherMiddleware(NotFound(), {
    "/app1": app1,
    '/app2': app2,
    '/app3': app3
})

if __name__ == "__main__":
    app.run()

app1 到 app3 init.py

from flask import Flask

app = Flask(__name__)

@app.route("/")
def index_one():
    return "Hi im 1 or 2 or 3"

if __name__ == "__main__":
    app.run()

工作

python dispatcher.py

localhost:5000/app1 "Hi im one"
localhost:5000/app2 "Hi im two"
localhost:5000/app3 "Hi im three"

另一种配置

您可以导入另一个应用程序，例如 app0 并向应用程序添加菜单，使用 NotFound()

更改此设置

这有帮助

Application Dispatching

如何使用 WSGI 实现 Flask 应用按路径调度？

How to implement Flask Application Dispatching by Path with WSGI?

python

path

flask

wsgi

dispatch