如何使用 Python REGEX 重新排序字符串（无论它是怎样的）

Question

我是玩 REGEX 的新手，我遇到了困难...我正在尝试使用 Python re 重新排序字符串。这是一个简单的例子，这就是我所拥有的：

str = "one two three for"

但问题是：我不知道顺序。有时它可能是 "three two for one"，它可能是 "for three two one"、"one for two three" 或其他什么......我只需要一个正则表达式来使它成为 "one two three for" 无论如何。我想像这样的东西：

str = re.sub(r"some regex here", "   ", str)  #/1 => one, /2 => two, /3 => three, /4 => for

我什至不知道这是否有意义，或者是否有可能，哈哈，但我想你们理解我的意思。那么，你会怎么做呢？非常感谢！

Answer 1

您可以执行以下操作：

import re
s = "one two three for"
r = re.compile('(\S* )(\S* )(\S* )(\S*)')
print(r.sub(r'',s))

输出：

two one three for

Answer 2

这似乎有点蛮力，但就是这样，尝试一个接一个匹配 one or two or three

代码：

import re 
sentences = ['some sentence -> one two three',
             'some other sentence ->  two three one ',
             'this is a different ->  three two one',
             'statment -> three one two',
             'this is one two statement -> two one three']
for sentence in sentences:
    print(re.sub("(one|two|three)\s+(one|two|three)\s+(one|two|three)", "one two three", sentence))

输出：

some sentence -> one two three
some other sentence ->  one two three 
this is a different ->  one two three
statment -> one two three
this is one two statement -> one two three

如何使用 Python REGEX 重新排序字符串（无论它是怎样的）

How to reorder a string (no matter how it is) using Python REGEX

python

regex

capturing-group