JMeter

Question

import net.minidev.json.parser.JSONParser;
import net.minidev.json.JSONObject;
import net.minidev.json.JSONArray;

JSONParser p = new JSONParser(JSONParser.MODE_PERMISSIVE);

String response = prev.getResponseDataAsString();
JSONObject jsonresponse = (JSONObject) p.parse(response);
JSONObject json2 = (JSONObject) jsonresponse.get("Key1");

JSONObject newjson = new JSONObject();
newjson.put("displayValue", json2.get("displayValue"));
newjson.put("value", json2.get("value"));

jsonresponse.put("Key2", newjson);

if(jsonresponse.has("Key3"))
{
    jsonresponse.remove("Key3");
    jsonresponse.put("Key3", jsonresponse.get("Key3").get("value");     
}

log.info(jsonresponse.toString());

我需要进入 if 循环以删除 json 键值（如果存在）并将其替换为其他值。

Answer 1

我认为您至少需要将 if(jsonresponse.has("Key3")) 行更改为 if(jsonresponse.containsKey("Key3"))
根据 JMeter Best Practices you should not be using Beanshell for scripting so consider switching to Groovy language, Groovy performs much better and moreover it has built-in JSON parsing/generating capabilities. See Apache Groovy - Why and How You Should Use It 文章进行全面解释、基准测试、示例代码片段等

JMeter - JSON 响应操作在具有 java 的 JSR223 处理器中不起作用

JMeter - JSON response manipulation is not working in JSR223 processor with java

beanshell

jsr223