如何使用正则表达式从 python 中的图像路径获取起始文本和结束文本？

Question

这里给出两个场景

示例 1

the Image Path is https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here
and the url was this and Click here to view the detail goes here

示例 2

https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here
Click here to view screenshot the detail goes here

我的代码如下

import re
 str_text = "the Image Path is https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here and the url was this and Click here to view the detail goes here"
urls = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', str_text)
print("Urls: ",":".join(urls))

结果

https://ictagrisindh.gov.pk/img/inauguration1.jpg

我想提取从起点到终点之间的文本 & 还想从图像路径中的任何地方提取文本

如有任何帮助，我们将不胜感激并提前致谢

Answer 1

import re

e1 = 'the Image Path is https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here' + \
'and the url was this and Click here to view the detail goes here'

e2 = 'https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here' + \
'Click here to view screenshot the detail goes here'

start_pattern = '(^.+)(?=http.+.jpg)'
image_url_pattern = '(http.+.jpg)'
end_pattern = '(?:^.+.jpg)(.+$)'

start = re.findall(start_pattern, e1)
url = re.findall(image_url_pattern, e1)
end = re.findall(end_pattern, e1)

print(f'start: {start}')
print(f'url: {url}')
print(f'end: {end}')

示例 1：

start: ['the Image Path is ']
url: ['https://ictagrisindh.gov.pk/img/inauguration1.jpg']
end: [' the detail goes hereand the url was this and Click here to view the detail goes here']

示例 2：

start: []
url: ['https://ictagrisindh.gov.pk/img/inauguration1.jpg']
end: [' the detail goes hereClick here to view screenshot the detail goes here']

如何使用正则表达式从 python 中的图像路径获取起始文本和结束文本？

how to get the starting text and ending text from image path in python using regex?

python-3.x

image-text