遍历字典以替换前导零？

Question

我想遍历此字典并找到任何具有前导零的 'id'，如下所示，然后将其替换为不带零的。所以 'id': '01001' 会变成 'id': '1001'

以下是获取我正在使用的数据的方法：

from urllib.request import urlopen
import json
with urlopen('https://raw.githubusercontent.com/plotly/datasets/master/geojson-counties-fips.json') as response:
    counties = json.load(response)

到目前为止，我一次只能获取一个 ID，但不确定如何循环获取所有 ID：

到目前为止我的代码：counties['features'][0]['id']

{ 'type': 'FeatureCollection',
 'features': [{'type': 'Feature',
   'properties': {'GEO_ID': '0500000US01001',
    'STATE': '01',
    'COUNTY': '001',
    'NAME': 'Autauga',
    'LSAD': 'County',
    'CENSUSAREA': 594.436},
   'geometry': {'type': 'Polygon',
    'coordinates': [[[-86.496774, 32.344437],
      [-86.717897, 32.402814],
      [-86.814912, 32.340803],
      [-86.890581, 32.502974],
      [-86.917595, 32.664169],
      [-86.71339, 32.661732],
      [-86.714219, 32.705694],
      [-86.413116, 32.707386],
      [-86.411172, 32.409937],
      [-86.496774, 32.344437]]]},
   'id': '01001'}
    ]
}

Answer 1

from urllib.request import urlopen
import json
with urlopen('https://raw.githubusercontent.com/plotly/datasets/master/geojson-counties-fips.json') as response:
    counties = json.load(response)

如果 id 与您的 JSON 结构相同，则遍历列表。并更新id 作为

counties['features'][0]['id'] = counties['features'][0]['id'].lstrip("0") lstrip 将从字符串中删除前导零。

Answer 2

假设您的字典 counties 有以下数据。您可以使用以下代码：

counties={'type': 'FeatureCollection', 
     'features': [ {'type': 'Feature','properties': {'GEO_ID': '0500000US01001','STATE': '01','COUNTY': '001','NAME': 'Autauga', 'LSAD': 'County','CENSUSAREA': 594.436},
    'geometry': {'type': 'Polygon','coordinates': [[[-86.496774, 32.344437],[-86.717897, 32.402814],[-86.814912, 32.340803],
      [-86.890581, 32.502974],
      [-86.917595, 32.664169],
      [-86.71339, 32.661732],
      [-86.714219, 32.705694],
      [-86.413116, 32.707386],
      [-86.411172, 32.409937],
      [-86.496774, 32.344437] ]] } ,'id': '01001'}, {'type': 'Feature','properties': {'GEO_ID': '0500000US01001','STATE': '01','COUNTY': '001','NAME': 'Autauga', 'LSAD': 'County','CENSUSAREA': 594.436},
    'geometry': {'type': 'Polygon','coordinates': [[[-86.496774, 32.344437],[-86.717897, 32.402814],[-86.814912, 32.340803],
      [-86.890581, 32.502974],
      [-86.917595, 32.664169],
      [-86.71339, 32.661732],
      [-86.714219, 32.705694],
      [-86.413116, 32.707386],
      [-86.411172, 32.409937],
      [-86.496774, 32.344437] ]] } ,'id': '000000000001001'} ]} 

for feature in counties['features']:
    feature ['id']=feature ['id'].lstrip("0")

print(counties)

Answer 3

这是使用 json 对象挂钩的更短更快的方法，

def stripZeroes(d):
    if 'id' in d:
        d['id'] = d['id'].lstrip('0')
        return d
    return d
with urlopen('https://raw.githubusercontent.com/plotly/datasets/master/geojson-counties-fips.json') as response:
    counties = json.load(response, object_hook=stripZeroes)

遍历字典以替换前导零？

Iterate through dictionary to replace leading zeros?

python

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