jooq query for sql 具有分析功能的查询

jooq query for sql query with analytical function

我有 sql 个类似

的查询
select *
from (
   select s.*, max(year) over () max_year
   from Transaction s
   where s.Account_Number     = '4234242234'
     and s.month in (0,1)) o
where o.year=o.max_year;

我需要用 jOOQ 编写,任何帮助。 我尝试了以下

dslContext.select(Transaction.BANK,
                    Transaction.ACCOUNT,
                    Transaction.AMOUNT,
                    max(Transaction.YEAR).over())
            .from(Transaction)
            .where(Transaction.BANK.eq(bank))
            .and(Transaction.MONTH.in((byte) 0, (byte) 1))
            .fetchInto(Transaction.class);

此外,有什么方法可以避免列出 select 中的所有列。而不是

select(Transaction.BANK,
       Transaction.ACCOUNT,
       Transaction.AMOUNT,
       max(Transaction.YEAR).over())

类似

select(Transaction.*,
       max(Transaction.YEAR).over())

派生的table可以这样构造:

// Assuming this static import, as always:
import static org.jooq.impl.DSL.*;

// Create aliased column expression for later reuse
Field<Integer> maxYear = max(Transaction.YEAR).over().as("max_year");

// Create derived table
Table<?> o = select(Transaction.asterisk(), maxYear)
            .from(Transaction)
            .where(Transaction.BANK.eq(bank))
            .and(Transaction.MONTH.in((byte) 0, (byte) 1))
            .asTable("o");

// Use derived table and dereference fields from it using Table.field(Field)
ctx.select()
   .from(o)
   .where(o.field(Transaction.YEAR).eq(o.field(maxYear)))
   .fetch();

Also, is there any way to avoid listing all columns in select

您正在寻找 Table.asterisk() to produce the asterisk in SQL, or Table.fields() 从您生成的代码中生成所有字段。