金额少于200多长时间

Question

我需要确定金额少于 200 的时间有多长。

我的数据集看起来像

Id user time amount max_amount
25 3618  1    0        1
25 3618  1    17040    3
25 3618  1    30       2
27 4281  1    0        1
27 4281  1    14188    3
27 4281  1    17372    4
27 4281  1    190      2

等等

生成它的代码如下：

Select t2.id, t2.user, t1.time, sum(t1.amount_amt as float) / (t1.eur_amt as float) as amount,
rank () over (partition by t2.user order by amount) max_amount
From table1
Inner join table2 as t2
on t1.user=t2.user
Group by 1,2,3

我的预期输出是

Id user time spent  
    25 3618  1    2
    27 4281  1    2

我怎么能得到这个结果？

Answer 1

我想你只是想要过滤和聚合：

select id, user, time, count(*)
from t
where amount < 200
group by id, user, time;

如果table是由问题中的代码生成的，您可以在上述查询之前使用CTE：

with t as (
      <query>
     )

金额少于200多长时间

how long an amount have been less than 200

sql

teradata

teradata-sql-assistant