有什么办法 replace/substitute uint8 数据中的数组数据点

Question

我有这个数据

old= array([[171, 171, 171, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       ...,
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17]], dtype=uint8)

在这个数据中我需要放置我的外部数组数据点

new= array([ 65, 108, 105,  32, 105, 115,  32, 116, 104, 101,  32,  66, 101,
       115, 116,  32, 105, 110,  32, 116, 104, 101,  32, 119, 111, 114,
       108, 100,  32, 121, 101, 101, 104, 104, 104, 104, 104, 104, 104,
       104])

在旧数组的第一行，这样输出就像

 old= array([[  65, 108, 105,  32, 105, 115,  32, 116, 104, 101,  32,66,101,
       115, 116,  32, 105, 110,  32, 116, 104, 101,  32, 119, 111, 114,
       108, 100,  32, 121, 101, 101, 104, 104, 104, 104, 104, 104, 104,
       104, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       [171, 171, 171, ..., 170, 170, 170],
       ...,
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17],
       [ 17,  17,  17, ...,  17,  17,  17]], dtype=uint8)

Answer 1

我假设您使用的是 numpy？有

old[0] = new[0]

工作？（假设您想将旧数组的第一行替换为新数组的第一行）

Answer 2

要替换数组的第一行：

old[0] = new

Answer 3

应该这样做：

old[0, :len(new)] = new

有什么办法 replace/substitute uint8 数据中的数组数据点

Is there any way to replace/substitute an array data points in uint8 data

python

arrays

numpy

image-processing

uint8t