使用 RASA 的 API 的正确方法是什么（rasa.core.processor - 遇到异常）？

Question

我安装了 rasa-demo 代码示例。为了打开 rasa API，我做了：

user@User:~/rasa-demo ‹master*›$ rasa run
No chat connector configured, falling back to the REST input channel. To connect your bot to another channel, read the docs here: https://rasa.com/docs/rasa/user-guide/messaging-and-voice-channels
2020-06-19 13:20:02 INFO     root  - Starting Rasa server on http://localhost:5005
2020-06-19 13:20:08 INFO     absl  - Using /var/folders/h5/9rj1zn8x4s59bk_mg_ktzv740000gn/T/tfhub_modules to cache modules.
2020-06-19 13:20:08 INFO     absl  - Downloading TF-Hub Module 'http://models.poly-ai.com/convert/v1/model.tar.gz'.
2020-06-19 13:20:26 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 22.35MB
2020-06-19 13:20:43 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 42.35MB
2020-06-19 13:21:02 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 82.35MB
2020-06-19 13:21:21 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 118.59MB
2020-06-19 13:21:40 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 148.59MB
2020-06-19 13:21:41 INFO     absl  - Downloaded http://models.poly-ai.com/convert/v1/model.tar.gz, Total size: 152.02MB
2020-06-19 13:21:41 INFO     absl  - Downloaded TF-Hub Module 'http://models.poly-ai.com/convert/v1/model.tar.gz'.
2020-06-19 13:22:14 INFO     root  - Rasa server is up and running.

如何作为 API 聊天机器人进行查询？我希望能够发出请求并通过请求进行对话，而不是使用 shell。到目前为止，当我尝试对 rasa 服务器进行卷曲时：

在：

user@User:~ $ curl -XPOST localhost:5005/webhooks/rest/webhook -d '{"message":"hi"}'

输出：

[]%

在 rasa 运行服务器上，我得到这样的响应：

2020-06-19 13:23:17 ERROR    rasa.core.actions.action  - Failed to run custom action 'action_greet_user'. Couldn't connect to the server at 'http://localhost:5055/webhook'. Is the server running? Error: Cannot connect to host localhost:5055 ssl:default [Connection refused]
2020-06-19 13:23:17 ERROR    rasa.core.processor  - Encountered an exception while running action 'action_greet_user'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.
2020-06-19 13:24:04 ERROR    rasa.core.actions.action  - Failed to run custom action 'action_greet_user'. Couldn't connect to the server at 'http://localhost:5055/webhook'. Is the server running? Error: Cannot connect to host localhost:5055 ssl:default [Connection refused]
2020-06-19 13:24:04 ERROR    rasa.core.processor  - Encountered an exception while running action 'action_greet_user'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.

它不工作。 作为 API 请求 Rasa 服务器的正确方法是什么？ 阅读 docs 后，我不清楚如何正确使用 API.

我也试过这个：

在：

import requests

response = requests.get('http://localhost:5005/webhooks/rest/webhook') 
print(response) 
print(response.headers) 
print(response.content)

输出：

<Response [405]>
{'Connection': 'keep-alive', 'Keep-Alive': '5', 'Allow': 'POST', 'Access-Control-Allow-Credentials': 'true', 'Content-Length': '60', 'Content-Type': 'text/plain; charset=utf-8'}
b'Error: Method GET not allowed for URL /webhooks/rest/webhook'

Answer 1

要访问 REST 端点，您应该使用 rasa run command instead. That will start a Rasa server, enabling any channels you've defined in your credentials file（如果未提供该文件，Rasa 将默认启用 REST 通道）。

然后您可以按照您在 post 中描述的方式查询端点，查看有关请求格式的更多详细信息 here。

Answer 2

我最后发现你是这样请求终点的：

localhost:5005/model/parse -s -d '{ "text": "hi" }'

文档应该更清楚。

Answer 3

尝试启动 rasa 服务器：rasa run --enable-api 它对我有用。

使用 RASA 的 API 的正确方法是什么（rasa.core.processor - 遇到异常）？

What is the correct way of using RASA's API (rasa.core.processor - Encountered an exception)?

python

nlp

python-requests

rasa-core

rasa