如何将信息从一个意图传递到另一个意图
How to pass information from one intent to another
使用Google登录帐户链接,我已阅读用户电子邮件。
我如何将此对话数据传递给下一个意图?
app.intent("Get Signin",(conv , params, signin) =>{
if(signin.status === 'OK'){
const email = conv.user.email
conv.ask(`I got your email as ${email}. How would you like to redeem?`)
conv.ask(new Suggestions(['QR code'],['16 digit code'],['Cancel']))
}
else
{
conv.close("Please sign in to redeem");
}
})
app.intent("numcode",(conv,{num, points}) => {
const mailOptions = {
from: "abc",
to: email,
subject: "YAY!",
html: `<p>Hello !! <br> You have ${points} in (${num}). </p>`
}
transporting.sendMail(mailOptions, (err, info) => {
if(err)
{
console.log(err);
}
})
conv.ask("You have succesfully finished.");
})
我想向用户发送邮件,所以应该用 "to: email" 替换什么或者应该在我的代码中添加什么。
您不必将其传递给您的下一个意图。一旦您的用户通过 accountlinking 登录,用户的电子邮件就可以通过 conv 对象获得。您可以调用 conv.user.email
来检索它。当您的用户触发您的 numcode 意图时,它应该用用户的电子邮件填写 属性。
在您的邮件选项中,您可以执行以下操作:
const mailOptions = {
from: "abc",
to: conv.user.email,
subject: "YAY!",
html: `<p>Hello !! <br> You have ${points} in (${num}). </p>`
}
使用Google登录帐户链接,我已阅读用户电子邮件。 我如何将此对话数据传递给下一个意图?
app.intent("Get Signin",(conv , params, signin) =>{
if(signin.status === 'OK'){
const email = conv.user.email
conv.ask(`I got your email as ${email}. How would you like to redeem?`)
conv.ask(new Suggestions(['QR code'],['16 digit code'],['Cancel']))
}
else
{
conv.close("Please sign in to redeem");
}
})
app.intent("numcode",(conv,{num, points}) => {
const mailOptions = {
from: "abc",
to: email,
subject: "YAY!",
html: `<p>Hello !! <br> You have ${points} in (${num}). </p>`
}
transporting.sendMail(mailOptions, (err, info) => {
if(err)
{
console.log(err);
}
})
conv.ask("You have succesfully finished.");
})
我想向用户发送邮件,所以应该用 "to: email" 替换什么或者应该在我的代码中添加什么。
您不必将其传递给您的下一个意图。一旦您的用户通过 accountlinking 登录,用户的电子邮件就可以通过 conv 对象获得。您可以调用 conv.user.email
来检索它。当您的用户触发您的 numcode 意图时,它应该用用户的电子邮件填写 属性。
在您的邮件选项中,您可以执行以下操作:
const mailOptions = {
from: "abc",
to: conv.user.email,
subject: "YAY!",
html: `<p>Hello !! <br> You have ${points} in (${num}). </p>`
}