如何计算来自单独列的两个字符串之间的归一化editex相似度

Question

我正在尝试使用 python 计算两个字符串之间的归一化 editex 相似度。 ASo far 我已经使用这个代码来获得工作正常的原始 editex 距离：

new_df["EdxScore"] = new_df.apply(lambda x: editex.(x[0],x[1]), axis=1)

我已阅读此处的文档：https://anhaidgroup.github.io/py_stringmatching/v0.3.x/Editex.html

但是当我尝试时：

new_df["EdxScore"] = new_df.apply(lambda x: textdistance.editex.get_sim_score(x[0],x[1]), axis=1)

我收到错误：

AttributeError: ("'Editex' 对象没有属性 'get_sim_score'", 'occurred at index 0')

我不完全确定这里出了什么问题，所以非常感谢您的帮助！

Answer 1

原来我没有正确阅读文档和定义要使用的参数。

为清楚起见，我粘贴了以下参数：

所有算法都有 2 个接口：

Class with algorithm-specific params for customizing.
Class instance with default params for quick and simple usage.

所有算法都有一些共同的方法：

.distance(*sequences) – calculate distance between sequences.
.similarity(*sequences) – calculate similarity for sequences.
.maximum(*sequences) – maximum possible value for distance and similarity. For any sequence: distance + similarity == maximum.
.normalized_distance(*sequences) – normalized distance between sequences. The return value is a float between 0 and 1, where 0 means equal, and 1 totally different.
.normalized_similarity(*sequences) – normalized similarity for sequences. The return value is a float between 0 and 1, where 0 means totally different, and 1 equal.

最常见的初始化参数：

qval – q-value for split sequences into q-grams. Possible values:
    1 (default) – compare sequences by chars.
    2 or more – transform sequences to q-grams.
    None – split sequences by words.
as_set – for token-based algorithms:
    True – t and ttt is equal.
    False (default) – t and ttt is different.

https://pypi.org/project/textdistance/

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