是否可以转储核心但不退出进程？

Question

我希望能够生成核心转储但之后不退出进程。我不需要它来继续执行，只是不要死。这是一个 C++ Ubuntu 进程。

我相信我正在以一种非常标准的方式转储核心：我通过使用 signal() 设置信号处理程序来捕获有问题的信号，我通过 setrlimit() 设置核心大小限制，然后我提示核心使用 signal() 和 raise() 转储：

signal(SIGSEGV, OnPosixSignal);

...

void OnPosixSignal(int iSignal)
{
    struct rlimit CoreLimit;
    CoreLimit.rlim_cur = RLIM_INFINITY;
    CoreLimit.rlim_max = RLIM_INFINITY;
    setrlimit(RLIMIT_CORE, &CoreLimit);
    signal(iSignal, SIG_DFL);
    raise(iSignal);
}

有什么办法可以在转储核心后不让进程退出？

提前致谢！

Answer 1

您也可以使用 gcore:

Generate a core dump of a running program with process ID pid. Produced file is equivalent to a kernel produced core file as if the process crashed (and if "ulimit -c" were used to set up an appropriate core dump limit). Unlike after a crash, after gcore the program remains running without any change.

是否可以转储核心但不退出进程？

Is it possible to dump the core but not exit the process?

c

c++

ubuntu

core