如何用xquery查询单个节点，使结果有不同的标签？

Question

如何 adjust 下面的 xquery 使得结果是：

<?xml version="1.0" encoding="UTF-8"?><Sex>F</Sex>

xml:

<csv>
  <record>
    <entry>Reported_Date</entry>
    <entry>HA</entry>
    <entry>Sex</entry>
    <entry>Age_Group</entry>
    <entry>Classification_Reported</entry>
  </record>
  <record>
    <entry>2020-01-26</entry>
    <entry>Vancouver Coastal</entry>
    <entry>M</entry>
    <entry>40-49</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-02</entry>
    <entry>Vancouver Coastal</entry>
    <entry>F</entry>
    <entry>50-59</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-05</entry>
    <entry>Vancouver Coastal</entry>
    <entry>F</entry>
    <entry>20-29</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-05</entry>
    <entry>Vancouver Coastal</entry>
    <entry>M</entry>
    <entry>30-39</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-11</entry>
    <entry>Interior</entry>
    <entry>F</entry>
    <entry>30-39</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-20</entry>
    <entry>Fraser</entry>
    <entry>F</entry>
    <entry>30-39</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-21</entry>
    <entry>Fraser</entry>
    <entry>M</entry>
    <entry>40-49</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-27</entry>
    <entry>Vancouver Coastal</entry>
    <entry>F</entry>
    <entry>60-69</entry>
    <entry>Lab-diagnosed</entry>
  </record>
</csv>

xquery:

declare namespace map = "http://www.w3.org/2005/xpath-functions/map";
declare namespace array = "http://www.w3.org/2005/xpath-functions/array";

declare namespace output = "http://www.w3.org/2010/xslt-xquery-serialization";

for $x in /csv

return $x/record[3]/entry[3]

结果：

<?xml version="1.0" encoding="UTF-8"?><entry>F</entry>

Answer 1

试试看

for $x in /csv
return
<Sex>
  {$x/record[3]/entry[3]/text()}
</Sex>

输出：

<?xml version="1.0" encoding="UTF-8"?><Sex>F</Sex>

Answer 2

或者如果你像我一样不喜欢不必要的变量，你也可以这样做（在 3.1 中）

/csv/record[3]/entry[3] ! <Sex>{string(.)}</Sex>

如何用xquery查询单个节点，使结果有不同的标签？

How to query a single node with xquery so that the result has a different tag?

xml

xml-parsing

nosql

xquery

flwor