子矩阵右对角线 - Python

Question

程序必须接受大小为 RxC 的整数矩阵和一个整数 K，因为 input.The 程序必须打印左下角到顶部的所有整数 right diagonal 在每个 KxK 子矩阵中没有给定矩阵的任何重叠

NOTE: The values of R and C ara always multiples of K

示例：

我的代码：

row , col = map(int,input().split())
mat = [list(map(int,input().split())) for i in range(row)]
k = int(input())
temp = k
# To store the right diagonal elements of all the sub matrices 
right_diagonal_elements = []
for i in range(row):
    te =temp
    # Iterating through the matrix in such a way
    #that it appends only the k th element ,
    #then k-1, and so on til the first element
    while te<=col:
        # It appends the right diagonal element but in a different order
        right_diagonal_elements.append(mat[i][te-1])
        te+=k
    if temp == 1:
        temp = k
        continue
    temp -= 1

在这段代码中，我的代码获得了所有正确的对角线元素，但我一直在思考如何安排它以获得给定的输出
对于上面的示例，right_diagonal_elements 具有 [2, 4, 5, 7, 5, 1, 6, 0]。我坚持如何在列表中排列这些元素以获得示例

中的输出

Answer 1

如果你想打印所有子矩阵的右对角线那么

R, C = map(int, input().split())
mat = [list(map(int, input().split())) for _ in range(R)]
K = int(input())
#iterating from k-1 to R by K
for i in range(K - 1, R, K):
    # Iterating j from 0 to C by K
    for j in range(0, C, K):
        # Iterating through the sub matrix of size KxK
        for p in range(K):

            print(mat[i-p][j+p], end=' ')
        print()

子矩阵右对角线 - Python

Sub Matrices right diagonal - Python

python-3.x

list

matrix

submatrix