将数组中的分隔字符串值分隔为布尔变量
Separate delimited string values in array into boolean variables
我有一个数据集,它在一个字符串数组中列出了每天完成的不同活动,类似的概念被问到 。每个 activity 都是分隔的,可以很容易地分成几列,正如我在 Excel.
中所做的那样没有问题
activites
Work | family | date | gaming | relax | good sleep | shopping
Work | family | date | Nature | Crusin | reading | gaming | relax | good sleep | cooking | laundry
family | date | movies & tv | gaming | sport | relax | medium sleep | cooking
Work | family | date | Photography | gaming | relax | good sleep | medium sleep | cooking
Work | family | date | Nature | reading | gaming | relax | good sleep | cleaning
我想做的是将每个 activity 变成一个布尔变量,它有自己的列,所以它表示 0
没有完成 activity那天和 1
完成了 activity。它看起来像这样:
Work Family Date Gaming Relax
1 1 0 1 0
1 1 1 0 0
0 0 1 0 1
所以,我最终做的是利用我的 Java 知识重新格式化数据。我首先将活动分成它们自己的变量,每个变量都包含一个数字(二进制)值,以指示 activity 那天是否已经完成。我不得不单独对待睡眠质量,所以这部分看起来有点不稳定。这是产生正确输出的代码:
public static void main(String[] args) throws FileNotFoundException {
Scanner scan = new Scanner(new FileReader("activities.txt"));
String[] actList = { "Work", "school", "family", "friends", "date", "nature", "crusin", "photography",
"making music/piano", "movies & tv", "reading", "gaming", "sport", "relax", "sleep", "shopping", "cleaning",
"cooking", "laundry" };
int row = 0;
while (scan.hasNextLine()) {
row++;
int col = 0;
int activityNo = 0;
int[] actValue = new int[actList.length];
String pipeDelim = scan.nextLine();
String[] actName = pipeDelim.split(" \| ");
int sleepTagsUsed = 0;
while (activityNo < actName.length) {
col = 0;
for (String a : actName) {
if (a.contains("sleep")) {
col = 14;
if (a.equalsIgnoreCase("bad sleep") || a.equalsIgnoreCase("bad sleep\t")) {
if (col < actList.length) {
actValue[col] = 0;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else if (a.equalsIgnoreCase("medium sleep") || a.equalsIgnoreCase("medium sleep\t")) {
if (col < actList.length) {
actValue[col] = 1;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else if (a.equalsIgnoreCase("good sleep") || a.equalsIgnoreCase("good sleep\t")) {
if (col < actList.length) {
actValue[col] = 2;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else if (a.equalsIgnoreCase("sleep early") || a.equalsIgnoreCase("sleep early\t")) {
if (col < actList.length) {
actValue[col] = 3;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else {
if (col < actList.length) {
actValue[col] = -1;
} else {
break;
}
System.out.println("No sleep logged error");
}
} else {
int j = 0;
for (String i : actList) {
if (a.equalsIgnoreCase(i) || a.equalsIgnoreCase(i + "\t")) {
actValue[col] = 1;
if (activityNo > actName.length) {
break;
} else {
activityNo++;
break;
}
} else {
if (col < actList.length) {
j++;
if (j > col) {
actValue[col] = 0;
col++;
}
} else {
break;
}
}
}
col++;
}
}
}
for (int p : actValue) {
System.out.print(p + "\t");
}
System.out.println();
}
scan.close();
}
我有一个数据集,它在一个字符串数组中列出了每天完成的不同活动,类似的概念被问到
activites
Work | family | date | gaming | relax | good sleep | shopping
Work | family | date | Nature | Crusin | reading | gaming | relax | good sleep | cooking | laundry
family | date | movies & tv | gaming | sport | relax | medium sleep | cooking
Work | family | date | Photography | gaming | relax | good sleep | medium sleep | cooking
Work | family | date | Nature | reading | gaming | relax | good sleep | cleaning
我想做的是将每个 activity 变成一个布尔变量,它有自己的列,所以它表示 0
没有完成 activity那天和 1
完成了 activity。它看起来像这样:
Work Family Date Gaming Relax
1 1 0 1 0
1 1 1 0 0
0 0 1 0 1
所以,我最终做的是利用我的 Java 知识重新格式化数据。我首先将活动分成它们自己的变量,每个变量都包含一个数字(二进制)值,以指示 activity 那天是否已经完成。我不得不单独对待睡眠质量,所以这部分看起来有点不稳定。这是产生正确输出的代码:
public static void main(String[] args) throws FileNotFoundException {
Scanner scan = new Scanner(new FileReader("activities.txt"));
String[] actList = { "Work", "school", "family", "friends", "date", "nature", "crusin", "photography",
"making music/piano", "movies & tv", "reading", "gaming", "sport", "relax", "sleep", "shopping", "cleaning",
"cooking", "laundry" };
int row = 0;
while (scan.hasNextLine()) {
row++;
int col = 0;
int activityNo = 0;
int[] actValue = new int[actList.length];
String pipeDelim = scan.nextLine();
String[] actName = pipeDelim.split(" \| ");
int sleepTagsUsed = 0;
while (activityNo < actName.length) {
col = 0;
for (String a : actName) {
if (a.contains("sleep")) {
col = 14;
if (a.equalsIgnoreCase("bad sleep") || a.equalsIgnoreCase("bad sleep\t")) {
if (col < actList.length) {
actValue[col] = 0;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else if (a.equalsIgnoreCase("medium sleep") || a.equalsIgnoreCase("medium sleep\t")) {
if (col < actList.length) {
actValue[col] = 1;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else if (a.equalsIgnoreCase("good sleep") || a.equalsIgnoreCase("good sleep\t")) {
if (col < actList.length) {
actValue[col] = 2;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else if (a.equalsIgnoreCase("sleep early") || a.equalsIgnoreCase("sleep early\t")) {
if (col < actList.length) {
actValue[col] = 3;
if (sleepTagsUsed == 0) {
col++;
}
sleepTagsUsed++;
} else {
break;
}
if (!(activityNo > actName.length)) {
activityNo++;
}
} else {
if (col < actList.length) {
actValue[col] = -1;
} else {
break;
}
System.out.println("No sleep logged error");
}
} else {
int j = 0;
for (String i : actList) {
if (a.equalsIgnoreCase(i) || a.equalsIgnoreCase(i + "\t")) {
actValue[col] = 1;
if (activityNo > actName.length) {
break;
} else {
activityNo++;
break;
}
} else {
if (col < actList.length) {
j++;
if (j > col) {
actValue[col] = 0;
col++;
}
} else {
break;
}
}
}
col++;
}
}
}
for (int p : actValue) {
System.out.print(p + "\t");
}
System.out.println();
}
scan.close();
}