捕获异常并使用 C# Nunit 断言它

Question

我正在做一个阴性测试，我期待得到一个例外。所以我只想知道如何捕获异常消息然后断言它。

[Then(@"I create the (.*)")]
    public void ThenICreateTheContact(string entityName)
    {
        entityId = m_OrgServ.Create(entity);
    }

    [Then(@"I verify the exception")]
    public void ThenIVerifyTheException()
    {
        ScenarioContext.Current.Pending();
    }

这是个例外 -

Generic Exception caught: contact With Id = 81b10448-49b2-ea11-aacb-067e3e789e92 Does Not ExistSystem.ServiceModel.FaultException`1[Microsoft.Xrm.Sdk.OrganizationServiceFault]: Generic Exception caught: contact With Id = 81b10448-49b2-ea11-aacb-067e3e789e92 Does Not Exist (Fault Detail is equal to Exception details:

我做m_OrgServ.Create(entity)时出现异常；所以我想捕获它，然后在我展示的下一个方法中断言它的消息。

Answer 1

您可以使用 TestDelegate。

    private TestDelegate _create;
    
    [Then(@"I create the (.*)")]
    public void ThenICreateTheContact(string entityName)
    {
        _create = () => m_OrgServ.Create(entity);
    }

    [Then(@"I verify the exception")]
    public void ThenIVerifyTheException()
    {
      var exception = Assert.Throws<FaultException<OrganizationServiceFault>>(_create);
      Assert.That(exception.Message, Is.EqualTo("expected message here"));
    }

捕获异常并使用 C# Nunit 断言它

Catch the exception and assert it using C# Nunit

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exception

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