从以逗号分隔的列表中加入 table 获取多个列值

Question

我有 3 个 tables，其中包含如下行：

RESEARCH_REPORTS table:

REPORT_ID   TOPIC
141         My Report Topic Title
142         Another Report Topic Title
143         Yet Another Report Topic Title
...

PROGRAM_AREAS_REPORTS_REL table:

REPORT_ID    PROGRAM_AREA_ID
141          6
141          11
141          12
...

PROGRAM_AREAS table:

PROGRAM_AREA_ID    TITLE
6                  Program Area One
11                 Program Area Two
12                 Program Area Three
...

此查询目前正在向我返回以下结果：

SELECT rr.report_id, rr.topic, pa.title as program_areas 
FROM RESEARCH_REPORTS rr 
INNER JOIN PROGRAM_AREAS_REPORTS_REL parr ON rr.report_id = parr.report_id 
INNER JOIN PROGRAM_AREAS pa ON parr.program_area_id = pa.program_area_id 
WHERE rr.report_id = 141

查询结果:

report_id    topic                    program_areas
141          My Report Topic Title    Program Area One
141          My Report Topic Title    Program Area Two
141          My Report Topic Title    Program Area Three

我需要一个 select 查询，结果格式如下：

首选查询结果:

report_id    topic                    program_areas
141          My Report Topic Title    Program Area One, Program Area Two, Program Area Three    

如何在我当前的查询中完成此操作？

Answer 1

使用string_agg()函数：-

SELECT rr.report_id, rr.topic, string_agg(pa.title,',') as program_areas 
FROM RESEARCH_REPORTS rr 
INNER JOIN PROGRAM_AREAS_REPORTS_REL parr ON rr.report_id = parr.report_id 
INNER JOIN PROGRAM_AREAS pa ON parr.program_area_id = pa.program_area_id 
WHERE rr.report_id = 141
group by rr.report_id, rr.topic