SQL

Question

下面以table为例

ID Name Status
1  Jon  pass
2  Jon  fail
3  Jon  fail
4  Snow pass
5  Snow fail
6  Snow fail

我需要编写一个查询，以下面的格式显示结果

Name Total Pass Fail
Jon  3     1    2
Snow 3     1    2

我正在尝试使用 select 中的子查询进行以下查询，但我知道它不正确。请指教

SELECT 
    Name, 
    count(ID) as Total,
    (SELECT count(ID) FROM results WHERE status = 'pass') as Pass
    (SELECT count(ID) FROM results WHERE status = 'fail') as Fail
FROM results
HAVING count(ID)>2 
GROUP BY Name 
ORDER BY count(ID) desc;

Answer 1

您可以使用条件聚合来完成：

SELECT 
    Name, 
    COUNT(ID) as Total,
    COUNT(CASE WHEN status = 'pass' THEN 1 END) Pass,
    COUNT(CASE WHEN status = 'fail' THEN 1 END) Fail
FROM results
GROUP BY Name 
HAVING COUNT(ID) > 2
ORDER BY COUNT(ID) desc;

我保留了 HAVING 子句（必须放在 GROUP BY 之后），因为您在代码中使用它。

参见demo。
结果：

> NAME | TOTAL | PASS | FAIL
> :--- | ----: | ---: | ---:
> Jon  |     3 |    1 |    2
> Snow |     3 |    1 |    2

Answer 2

试试下面的脚本-

SELECT 
Name, 
count(ID) as Total,
SUM(CASE WHEN status = 'pass' THEN 1 ELSE 0 END)  as Pass,
SUM(CASE WHEN status = 'fail' THEN 1 ELSE 0 END)  as fail
FROM results
GROUP BY Name 
HAVING count(ID)>2 
ORDER BY count(ID) desc;

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