MVC：使用 Bootstrap 按钮将参数发送到控制器中的操作

Question

查看：

@using (Html.BeginForm("UpdateMaterial", "MyController", FormMethod.Post, Model.MaterialId))
    {
    @Html.AntiForgeryToken()
    <input type="submit" class="btn btn-primary custom" value="Derivate Material" />
    }

控制器：

[HttpPost]
public ActionResult UpdateMaterial(int? matId)
        {
            if (matId == null)
            {
                return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
            }
        //do something here
        }

我发送的Id总是空的。我该如何更改？

Answer 1

您的 Model.MaterialId 应该是一个表单元素：

@using (Html.BeginForm("UpdateMaterial", "MyController", FormMethod.Post))
{
     @Html.HiddenFor(model => model.MaterialId)

     @Html.AntiForgeryToken()
     <input type="submit" class="btn btn-primary custom" value="Derivate Material" />
}

此外，您应该更改操作定义并使其接受模型的类型，而不是 int?:

[HttpPost]
public ActionResult UpdateMaterial(MyModelType model)
{
     if (model.matId == null)
     {
         return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
     }
     //do something here
}